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What is an easy way to go the quadratic formula?
the quadratic formula is really complex. so, if you can avoid it, you should. one way i do this is by getting the trinomial into X^2 - 2YX + Y^2 = 0 form. here's an example lets say we have x^2 - 2x - 5 = 0 normally we would have to do the quadratic formula however, if we get it into this form, we can get x^2 - 2(1)x + 1 = 6 all i did was add 6 to both sides of the equation. you can now simplify the left side of the equation, and be left with (x-1)^(2) = 6 to get ride of the exponent on the left side, find the square root of both sides. this will leave you with (x-1) = (+ or -)radical(6) add one to both sides and you will get x = 1 (+ or -)radical(6) therefore, x can equal 1 + radical(6) or 1 - radical(6) now, this may seem complex, but it is easy once you get used to it. It is far more efficient than the long quadratic formula.
Is there a formula for solving quadratic equations?
x is equal to negative b plus or minus the square root of b squared minus 4 times "a" times "c" all over 2 times "a"
What expressions appear as a step in solving 3x2 equal x-5 using the quadratic formula?
The following is the answer:
If the right-hand side of a quadratic equation does not equal zero you need to the number or expression on the righthand side from both sides before you can use the quadratic formula?
subtract
Where quadratic equation is applicable?
A quadratic equation in its general form of ax2+bx+c = 0 whereas 'a' is equal or greater than 1 is applicable when finding the unknown variable of x by using the quadratic equation formula.
