Do you mean -4y2+32y-64 = 0 otherwise it's not an equation because there's no equal sign
If so then by using the quadratic equation formula the values of y both equal 4
If you mean: 4y^2 +3 -13y then the expression is (4y-1)(y-3) when factored
In the equation x = 4y2 + 6 where x = 42, we need to substitute 42 for x and solve for y. x = 4y2 + 6 42 = 4y2 + 6 42 - 6 = 4y2 + 6 - 6 36 = 4y2 36 / 2 = 4y2 / 2 18 = 4y 18 / 4 = 4y / 4 9 / 2 = y 4 1/2 = y (or 4.5 = y)
hyperbola
x3+8y3 = (x+2y)(x2-2xy+4y2) The discriminant of the quadratic factor is 4y2-16y2 < 0 so there are no real roots. So the only real root of the original polynomial is x+2y=0 or x = -2y
4y2 + 25y + 6
4y2+37a-15=0
If you mean: 4y^2 +3 -13y then the expression is (4y-1)(y-3) when factored
In the equation x = 4y2 + 6 where x = 42, we need to substitute 42 for x and solve for y. x = 4y2 + 6 42 = 4y2 + 6 42 - 6 = 4y2 + 6 - 6 36 = 4y2 36 / 2 = 4y2 / 2 18 = 4y 18 / 4 = 4y / 4 9 / 2 = y 4 1/2 = y (or 4.5 = y)
Without an equality sign it is not an equation but the expression can be factored as (2y-3)(2y+3)
hyperbola
(4y2 + 3)(4y2 - 6y + 3)(4y2 + 6y + 3)
x3+8y3 = (x+2y)(x2-2xy+4y2) The discriminant of the quadratic factor is 4y2-16y2 < 0 so there are no real roots. So the only real root of the original polynomial is x+2y=0 or x = -2y
4y2 + 25y + 6
To factor 4y^2 + 25y + 6, you can split the middle term by finding two numbers whose product is equal to 4 * 6 (the product of the first and last terms) and whose sum is equal to the coefficient of the middle term, which is 25. In this case, the numbers are 4 and 1. So, you can rewrite the expression as (4y + 1)(y + 6).
Multiply each item by 10 to give whole numbers then move items to give ay2+by+c=0 3.5y2+2.6y-8.2=4y2-6.9y multiply by 10 35y2 + 26y - 82 = 40y2 -69y subtract 35y2 from both sides 26y - 82=5y2 -69y subtract 26y from both sides -82 = 5y2 - 95y add 82 to each side 0 = 5y2 - 95y +82 or 5y2 - 95y +82 = 0
The answer to x2 - 2x - 4y2 - 4y =(x - 2y)(x - 2y - 2)
If you start with the following equation of an ellipse: x2/4 + y2/9 = c2 and transform the equation to 9x2/36 + 4y2/36 = 36c2 the denominators are the same but the equation is unchanged and so the ellipse remains exactly as it was before.