Do you mean -4y2+32y-64 = 0 otherwise it's not an equation because there's no equal sign
If so then by using the quadratic equation formula the values of y both equal 4
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If you mean: 4y^2 +3 -13y then the expression is (4y-1)(y-3) when factored
In the equation x = 4y2 + 6 where x = 42, we need to substitute 42 for x and solve for y. x = 4y2 + 6 42 = 4y2 + 6 42 - 6 = 4y2 + 6 - 6 36 = 4y2 36 / 2 = 4y2 / 2 18 = 4y 18 / 4 = 4y / 4 9 / 2 = y 4 1/2 = y (or 4.5 = y)
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x3+8y3 = (x+2y)(x2-2xy+4y2) The discriminant of the quadratic factor is 4y2-16y2 < 0 so there are no real roots. So the only real root of the original polynomial is x+2y=0 or x = -2y
4y2 + 25y + 6