Zn(s)/Zn2+(aq)//Au+(aq)/Au(s)
Reduced 60%
NO3-
no it can not be reduced.... :)
It cannot be reduced
Answer this question… Fe3+
Fe3 is the least likely to be reduced because it has the highest oxidation state among the listed elements, making it less prone to gaining electrons and being reduced.
Mg2+
Zn2+
Idontremember is right, Na+ was correct for me on Apex
Mg(NO3)2+ZN2+--->ZN2++2NO3-+Mg(s)
The theoretical voltage in an electrical circuit can be calculated using Ohm's Law, which states that voltage (V) equals the current (I) multiplied by the resistance (R), or V = I * R. This formula helps determine the voltage across a component in a circuit based on its resistance and the current flowing through it.
Zn2+ + 2e- <--> Zno -0.7618 V
The white color of Zn2+ complexes is attributed to the fact that Zn2+ lacks partially filled d orbitals for d-d electronic transitions that typically give rise to color in transition metal complexes. As a result, Zn2+ complexes do not absorb visible light in the range that produces color, leading to their white appearance.
When zinc becomes an ion, it is called a zinc ion, with a2+ charge. Its symbol is Zn2+.
Mg(s)
Mg(NO3)2+ZN2+--->ZN2++2NO3-+Mg(s)