NO3-
Na+ plus OH- plus H+ equals H2O plus Na+ plus Cl-
333 + 110 = 390 + 53
You would add 4.
x = 0 or x =-5
(0, 6)
The complete ionic equation for the reaction is: Ca^2+(aq) + 2NO3^-(aq) + 2K+(aq) + CO3^2-(aq) --> CaCO3(s) + 2K+(aq) + 2NO3^-(aq)
The net ionic equation for the reaction between KCl(aq) and Pb(NO3)2(aq) to form KNO3(aq) and PbCl2(s) is: 2K^+(aq) + 2NO3^-(aq) + Pb^2+(aq) + 2Cl^-(aq) -> 2K^+(aq) + 2NO3^-(aq) + PbCl2(s)
The spectator ions are NO3- in this reaction. They are present on both sides of the equation before and after the reaction takes place, so they do not participate in the reaction and can be considered spectators.
Na+ plus OH- plus H+ equals H2O plus Na+ plus Cl-
The complete ionic equation for this reaction is: 2H⁺(aq) + SO₄²⁻(aq) + Ca²⁺(aq) + 2I⁻(aq) → CaSO₄(s) + 2H⁺(aq) + 2I⁻(aq)
Ba2+(aq) + SO42-(aq) ---> BaSO4(S) Barium sulfate is insoluble in aqueous solution. Sodium nitrate is soluble so the sodium and nitrate ions are spectators that can be cancelled out from the ionic equation to give you this net ionic equation. Depending on the teacher, you may have to underline the products because it is a precipitate. (I posted this originally before signing up. Just a footnote).
The chemical equation is:Na + OH- + H+ + Cl- = Na+ + Cl- + H2O(l)
The complete ionic equation for copper sulfate (CuSO4) plus sodium carbonate (Na2CO3) is: Cu^2+ (aq) + SO4^2- (aq) + 2Na^+ (aq) + CO3^2- (aq) → CuCO3 (s) + Na2SO4 (aq). This equation shows the dissociation of all ions in the reactants and products.
The chemical equation is:Na + OH- + H+ + Cl- = Na+ + Cl- + H2O(l)
The net ionic equation for the given reaction is H+ (aq) + OH- (aq) → H2O (l)
AgNO3 + NaCl → AgCl + NaNO3 Net ionic equation: Ag⁺ + Cl⁻ → AgCl
H2SO4(aq) + CaI2(aq) -> CaSO4(s) + 2HI(aq)