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Not if it wants to stay a b
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Well, in the real world, a can only be a, but in algebra sometimes a can be c, although usually if that is the case it will be n or x, and not a at all. So, it just depends on your perspective really. How you look at it, and what you see as "b"ing at all... 2 b or not 2 b, right?
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Maria keeps her four stuffed bears lined up on a shelf over her bed how many arrangements of the bears are possible?
The answer is 4! (4 factorial), the same as 4x3x2x1, which equals 24 combinations. The answer is 24 and this is how: A b c d A b d c A c d b A c b d A d c b A d b c B c d a B c a d B d a c B d c a B a c d B a d c C d a b C d b a C a b d C a d b C b d a C b a d D a b c D a c b D b c a D b a c D c a b D c b a
What is b plus b plus b plus c plus c plus c plus c?
b+b+b+c+c+c+c =3b+4c
What is the negation of B is not between A and C?
The negation of B is not between A and C is = [(A < B < C) OR (C < B < A)] If A, B and C are numbers, then the above can be simplified to (B - A)*(C - B) > 0
Is it possible to use the associative property with subtraction?
No. There is a property of numbers called the distributive property that proves this wrong. a- ( b - c) is NOT the same as (a-b) -c because: a-(b-c) = a-b+c by the distributive property a-b+c = (a-b) + c by the definition of () (a-b)+c is not always equal to (a-b)-c
What are the property of addition and multiplication?
The properties of addition are: * communicative: a + b = b + a * associative: a + b + c = (a + b) + c = a + (b + c) * additive identity: a + 0 = a * additive inverse: a + -a = 0 The properties of multiplication: * communicative: a × b = b × a * associative: a × b × c = (a × b) × c = a × (b × c) * distributive: a × (b + c) = a × b + a × c * multiplicative identity: a × 1 = a * multiplicative inverse: a × a^-1 = 1
