It is |B - C|
Algebraic Properties of Real Numbers The basic algebraic properties of real numbers a,b and c are: Closure: a + b and ab are real numbers Commutative: a + b = b + a, ab = ba Associative: (a+b) + c = a + (b+c), (ab)c = a(bc) Distributive: (a+b)c = ac+bc Identity: a+0 = 0+a = a Inverse: a + (-a) = 0, a(1/a) = 1 Cancelation: If a+x=a+y, then x=y Zero-factor: a0 = 0a = 0 Negation: -(-a) = a, (-a)b= a(-b) = -(ab), (-a)(-b) = ab
Rate This AnswerThe transitive property states that if a relation holds between a and b and between b and c, then it also exists between a and c.So, if A=B AND B=C, THEN A=C
the distance from A to B is 24Km
transitive means for example, "if a=b and b=c, then a=c". reflexive means for example, "a=a, b=b, c=c, etc."
B is between A and C.
If you do not know whether a < c or c < a then it is much simpler in words. It is "b lies between a and c". Mathematically, it is min[0.5(a + c -|a - c|)] < b < min[0.5(a + c +|a - c|)].If you do know that a < c then it is simply a < b < c.
It is |B - C|
It is |B - C|
Algebraic Properties of Real Numbers The basic algebraic properties of real numbers a,b and c are: Closure: a + b and ab are real numbers Commutative: a + b = b + a, ab = ba Associative: (a+b) + c = a + (b+c), (ab)c = a(bc) Distributive: (a+b)c = ac+bc Identity: a+0 = 0+a = a Inverse: a + (-a) = 0, a(1/a) = 1 Cancelation: If a+x=a+y, then x=y Zero-factor: a0 = 0a = 0 Negation: -(-a) = a, (-a)b= a(-b) = -(ab), (-a)(-b) = ab
Rate This AnswerThe transitive property states that if a relation holds between a and b and between b and c, then it also exists between a and c.So, if A=B AND B=C, THEN A=C
There are no letters missing between B and C, they are adjacent to one another in the alphabet.
because b is in between of a and c
No. A can be independent of both B and C and this doesn't give use any information about the relationship between B and C.
Probably an arc, but it is not possible to be certain because there is no information on where or what point b and c are..
The letter between A and C
B