No, a fourth degree polynomial cannot touch the x-axis three times. A polynomial can touch the x-axis at an even number of points, which corresponds to the multiplicity of its roots. If it touches the x-axis at three points, one of those points would have to be of odd multiplicity, which would make the total multiplicity odd, contradicting the fact that a fourth degree polynomial has an even degree. Thus, it can touch the x-axis at either 0, 2, or 4 points.
I think that there is not .
Three fourths
One fourth times three sevenths is calculated by multiplying the numerators and denominators: ( \frac{1}{4} \times \frac{3}{7} = \frac{1 \times 3}{4 \times 7} = \frac{3}{28} ). Therefore, one fourth times three sevenths equals three twenty-eighths.
3/12
A polynomial will definitely have nonreal zeros if it has an odd degree and a negative leading coefficient. For example, the polynomial ( f(x) = -x^3 + 2 ) has a degree of 3, which is odd, and the leading coefficient is negative. By the Fundamental Theorem of Algebra, it must have at least one nonreal zero, as it cannot cross the x-axis an odd number of times while remaining entirely above or below it.
seventh degree polynomial x3 times x4 = x7
The degree is equal to the maximum number of times the graph can cross a horizontal line.
I think that there is not .
Three fourths
22.2
The "degree" is the highest power - in this case, the 3 in 4x3 (4 times to the third power).
Three fourth cup flour twenty two times is 16 cups.
One fourth times three sevenths is calculated by multiplying the numerators and denominators: ( \frac{1}{4} \times \frac{3}{7} = \frac{1 \times 3}{4 \times 7} = \frac{3}{28} ). Therefore, one fourth times three sevenths equals three twenty-eighths.
Three thirty-seconds
3.75
Answer:612 Answer:612
Three fourths times two is one and a half so if you add three fourths to that you will get two and one fourth.