No, if there is a sqaured variable, the equation is not linear.
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2m^2 - 8 -First you should factor out a two. --> 2(m^2-4) -You now have something squared minus something else squared; You have m squared minus 2 squared. Whenever you have something squared minus something squared as you do in this case, there is a simple rule to remember: You can reduce that expression into the quantity of the square root of the first number or variable plus the square root of the second number or variable Times the quantity of the square root of the first number or variable minus the second number or variable squared. --> In the case of your expression: ----> 2(m+2)(m-2)<-----
It is a linear expression with one variable, b. Since it is not an equation it cannot be solved.
It is an expression with a variable, x.It is an expression with a variable, x.It is an expression with a variable, x.It is an expression with a variable, x.
It is a linear expression with one variable, b. Since it is not an equation it cannot be solved.