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Sure. That's true of a median in every isosceles triangle,
and every median in an equilateral triangle.
In fact it is true for any median of any triangle. The two parts may not be the same shapes but they will have the same area. That is why the point where the three medians meet (centroid) is the centre of mass of a triangular lamina of uniform thickness.
What else can I help you with?
What area property does the median of a triangle have?
Each median divides the area of a triangle into halves.
An equilateral triangle and a square have equal perimeters what is the ratio of the area of the triangle to the area of the square?
If an equilateral triangle and a square have equal perimeters, then the ratio of the area of the triangle to the area of the square is 1:3.
How do you divide a triangle into 9 equal parts?
To divide a triangle into 9 equal parts, you can start by drawing lines from each vertex to the midpoints of the opposite sides, creating three smaller triangles within the original triangle. Then, subdivide each of these smaller triangles into three equal parts by connecting the midpoints of their sides. This method ensures that all parts are equal in area while maintaining the overall shape of the triangle.
Is the area of two parallelograms equal?
yes
Why do you have to divide the area of a triangle and not a parallelogram?
you do it because the triangle is half the size of the parallelogram
What area property does the median of a triangle have?
Each median divides the area of a triangle into halves.
If x be the length of a median of an equilateral triangle then its area is?
30
Show that the diagonals of parallelogram divide it into four triangles of equal area?
We know that diagonals of parallelogram bisect each other. Therefore, O is the mid-point of AC and BD. BO is the median in ΔABC. Therefore, it will divide it into two triangles of equal areas. Area (ΔAOB) = Area (ΔBOC) ... (1) In ΔBCD, CO is the median. Area (ΔBOC) = Area (ΔCOD) ... (2) Similarly, Area (ΔCOD) = Area (ΔAOD) ... (3) From equations (1), (2), and (3), we obtain Area (ΔAOB) = Area (ΔBOC) = Area (ΔCOD) = Area (ΔAOD) Therefore, it is evident that the diagonals of a parallelogram divide it into four triangles of equal area.
How do you divide single triangle into 5 equal parts?
Divide the base of the triangle into five equal lengths. Draw lines from the opposite vertex to each of these dividing points. The triangle will be divided into five parts, each with the same area. The base is 1/5 of the original base, and they all have the same height - the same as in the original triangle.
How do you estimate the area of a triangle?
To get the area of a triangle you multiply length by width and divide by two.
An equilateral triangle and a square have equal perimeters what is the ratio of the area of the triangle to the area of the square?
If an equilateral triangle and a square have equal perimeters, then the ratio of the area of the triangle to the area of the square is 1:3.
How do you divide a triangle into 9 equal parts?
To divide a triangle into 9 equal parts, you can start by drawing lines from each vertex to the midpoints of the opposite sides, creating three smaller triangles within the original triangle. Then, subdivide each of these smaller triangles into three equal parts by connecting the midpoints of their sides. This method ensures that all parts are equal in area while maintaining the overall shape of the triangle.
Is the area of two parallelograms equal?
yes
How you find the area of a triangle?
To find the area of a triangle, you have to multiply the base of the triangle and the height of the triangle, then divide the product of those numbers by two.
Why do you have to divide the area of a triangle and not a parallelogram?
you do it because the triangle is half the size of the parallelogram
How do you measure a shape that has four side that are not equal?
Draw a diagonal to divide it into two triangles; find the area of each triangle and add the answers.
How do you find the height when you know the Area and the base?
in a triangle double area and divide by base in a rectangle divide area by base
