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No because as the polygon gets smaller the angles and sides get biggerso they can't tessellate by themselves.

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Q: Can a regular polygon with more than 6 sides ever tessellate?
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How could you explain a polygon has more sides than angles?

I'd have to see one first. So far, no polygon I've ever seen had more sides than angles.


What is a 3000000000 sided polygon?

A 3,000,000,000 sided polygon is called a teragon. Polygons with such a large number of sides are typically referred to by their numerical prefix followed by "gon." The properties of a teragon would be similar to those of a regular polygon, with equal side lengths and interior angles, but it would be practically indistinguishable from a circle due to the extremely large number of sides.


Can you ever have a polygon that is regular and concave?

No. The total of the interior angles of a polygon is given by: total_of_interior_angles = 180° × (number_of_sides -2) A regular polygon has every interior angle the same, and the size of each angle is given by: size_of_interior_angle = total_of_interior_angles / number_of_sides → size_of_interior_angle = 180° × (number_of_sides -2) / number_of_sides But as number_of_sides - 2 is (always) less than number_of_sides, (number_of_sides -2) / number_of_sides is less than 1 and so the size_of_interior_angle is less than 180°. To be a concave polygon, at least one interior angle must be greater than 180°. But as a regular polygon has all interior angles less than 180°, no regular polygon can be concave.


What is the name of 2000000 sides polygon?

A polygon with 2,000,000 sides is called a 2,000,000-gon or a 2-million-gon. It is a type of polygon with an extremely high number of sides, making it a very complex geometric shape. The naming convention for polygons follows the pattern of adding the number of sides as a prefix to the suffix "-gon" to indicate the shape.


Does a polygon ever have more diagonals than sides?

The number of diagonals for a shape with x sides is (x²-3x)/2 The number of sides is x You want to know if x is ever less than (x²-3x)/2 or else (x²-3x)/2 - x > 0 (x² - 3x) / 2 - x > 0 (x² - 3x)/2 - (2x)/x > 0 x² - 3x - 2x > 0 x² - 5x > 0 x(x-5)>0 This only true if x<0 or x>5, and since a polygon cannot have less than 2 sides, x<0 is meaningless. This means that if x<5 then the number of diagonals is less than the number of sides, equal for x=5, and more for x>5. ■