Only if it is a square.
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∙ 10y agoNo. In fact, a rhombus cannot be cyclic - unless it is a square.
Yes, every subgroup of a cyclic group is cyclic because every subgroup is a group.
every abelian group is not cyclic. e.g, set of (Q,+) it is an abelian group but not cyclic.
A rhombus may be a square or just a rhombus (a rhombus is merely called a rhombus when there are no 90 degree angles).
Rhombus Not a SquareIn a square, the sides are perpendicular. In a rhombus, they aren't. A rhombus is never a square.
No. In fact, a rhombus cannot be cyclic - unless it is a square.
A rhombus cannot be a cyclic quadrilateral because its opposite angles are not supplementary (unless it is a square). It cannot, therefore, have a radius.
Many different quadrilaterals can have those angles. Depending upon the lengths of the sides, where the angles are and how many pairs of parallel sides it has, it could be: A cyclic quadrilateral, a trapezium, a parallelogram or a rhombus.
Yes, every subgroup of a cyclic group is cyclic because every subgroup is a group.
Meiosis is not cyclic; rather it is a linear process. It does not cycle.
A rhombus. A rhombus. A rhombus. A rhombus.
The word 'cyclic' is the adjective form of the noun cycle.
every abelian group is not cyclic. e.g, set of (Q,+) it is an abelian group but not cyclic.
A rhombus may be a square or just a rhombus (a rhombus is merely called a rhombus when there are no 90 degree angles).
If a coordinate is cyclic in the Lagrangian, then the corresponding momentum is conserved. In the Hamiltonian formalism, the momentum associated with a cyclic coordinate becomes the generalized coordinate's conjugate momentum, which also remains constant. Therefore, if a coordinate is cyclic in the Lagrangian, it will also be cyclic in the Hamiltonian.
the cyclic integral of this is zero
A rhombus can be anywhere.