Oh, dude, let me break it down for you. So, for a triangle to exist, the sum of the lengths of any two sides must be greater than the length of the third side. In this case, 20 + 20 is 40, which is equal to the third side length. So, no triangle here, just a straight line. Like, nice try, but not today.
No, it is not possible to draw a triangle with side lengths of 150, 20, and 20. In a triangle, the sum of the lengths of any two sides must be greater than the length of the third side according to the Triangle Inequality Theorem. In this case, 20 + 20 is less than 150, so the given side lengths do not satisfy this theorem, making it impossible to form a triangle.
Yes, you can form a triangle with the lengths 20, 22, and 24. According to the triangle inequality theorem, the sum of the lengths of any two sides must be greater than the length of the third side. In this case, 20 + 22 > 24, 20 + 24 > 22, and 22 + 24 > 20 are all true, confirming that these lengths can indeed form a triangle.
It is not possible because 9+8 is not greater than 20.
It is not possible to have a triangle with sides of those lengths. The two shortest sides of a triangle must always add to more than the longest side. This is known as the triangle inequality.
To determine the possible lengths for the third side of a triangle when two sides are 34 and 14, we can use the triangle inequality theorem. The sum of the lengths of any two sides must be greater than the length of the third side. Thus, the length of the third side must be less than 34 + 14 = 48 and greater than |34 - 14| = 20. Therefore, any length less than or equal to 20 or greater than or equal to 48 would not work for the third side.
No, it is not possible to draw a triangle with side lengths of 150, 20, and 20. In a triangle, the sum of the lengths of any two sides must be greater than the length of the third side according to the Triangle Inequality Theorem. In this case, 20 + 20 is less than 150, so the given side lengths do not satisfy this theorem, making it impossible to form a triangle.
Yes you can.
Yes, you can form a triangle with the lengths 20, 22, and 24. According to the triangle inequality theorem, the sum of the lengths of any two sides must be greater than the length of the third side. In this case, 20 + 22 > 24, 20 + 24 > 22, and 22 + 24 > 20 are all true, confirming that these lengths can indeed form a triangle.
It is not possible because 9+8 is not greater than 20.
It is not possible to have a triangle with sides of those lengths. The two shortest sides of a triangle must always add to more than the longest side. This is known as the triangle inequality.
To determine the possible lengths for the third side of a triangle when two sides are 34 and 14, we can use the triangle inequality theorem. The sum of the lengths of any two sides must be greater than the length of the third side. Thus, the length of the third side must be less than 34 + 14 = 48 and greater than |34 - 14| = 20. Therefore, any length less than or equal to 20 or greater than or equal to 48 would not work for the third side.
True
The lengths of the legs of a right triangle are 15 cm and 20 cm. What is the length of the hypotenuse?
Subtract the two side lengths from the perimeter. The perimeter of a triangle is just the length of the 3 sides added together. Eg. Q: A triangle has a perimeter of 20 m. One side is 5m and another is 10m. How long is the 3rd side? A: Perimeter - side 1 - side 2 = side 3 Side 3 = 20 - 5 - 10 = 5 m
TRUE
(3*202)+(1/2*20*17.32) = 1373.2 square feet
To determine if segments with lengths 9, 4, and 11 can form a triangle, we can use the triangle inequality theorem. This states that the sum of the lengths of any two sides must be greater than the length of the third side. In this case, 9 + 4 = 13, which is greater than 11; 9 + 11 = 20, which is greater than 4; and 4 + 11 = 15, which is greater than 9. Since all conditions are satisfied, the segments can indeed form a triangle.