Yes, you can form a triangle with the lengths 20, 22, and 24. According to the triangle inequality theorem, the sum of the lengths of any two sides must be greater than the length of the third side. In this case, 20 + 22 > 24, 20 + 24 > 22, and 22 + 24 > 20 are all true, confirming that these lengths can indeed form a triangle.
20 + [(21+23)/22]2 = 20 + [44/22]2 = 20 + 22 = 20 + 4 = 24
20 +2 = 22 so its not 24.. had it been 20+4 or 20+2+2 then it would be 24.
(20+29+22+25)/4 = 24
Expanded form is 20 + 4 = 24
22/24 simplified to lowest terms is 11/12.
A triangle with side a: 24, side b: 24, and side c: 20 units has an area of 218.17 square units.
22 + 9 - 20 + 13 = 24
24 + 18 + 20 + 22 = 84
(22/4)x8-20=24
22 and 24 theoretically.
22/24 = 11/12
20 + [(21+23)/22]2 = 20 + [44/22]2 = 20 + 22 = 20 + 4 = 24
A=1/2 B*h so the area of the triangle=1/2*(24)*(20)=240 sq. un.
10+12=22 thus 22+2=24 :) 20/10 = 2
4 20 = 22 x 5 24 = 23 x 3 gcd = 22 = 4
20
22/24 = 11/12