no because a²+b ²=c ².
Because 10²+10²=14.1
100+100=200
So you can't have 150 but you can have 200
No, it is not possible to draw a triangle with sides of 150 cm, 10 cm, and 10 cm. According to the triangle inequality theorem, the sum of the lengths of any two sides must be greater than the length of the third side. In this case, 10 cm + 10 cm is not greater than 150 cm.
no because a²+b ²=c ². Because 10²+10²=14.1 100+100=200 So you can't have 150 but you can have 200
5 x 10 = 50cm2
It is: 10*10 = 100 square cm
Area of square = (length of side)2 = (10cm)2 = 10*10 cm2 = 100 cm2
No, it is not possible to draw a triangle with sides of 150 cm, 10 cm, and 10 cm. According to the triangle inequality theorem, the sum of the lengths of any two sides must be greater than the length of the third side. In this case, 10 cm + 10 cm is not greater than 150 cm.
no because a²+b ²=c ². Because 10²+10²=14.1 100+100=200 So you can't have 150 but you can have 200
5 x 10 = 50cm2
It is: 10*10 = 100 square cm
All you do is add the sides up for the perimeter. 12 + 10 + 9 = 31
The length of the two equal sides is not enough information to uniquely determine the length of the base.With sides of 10 cm, you can draw a triangle with anybase that's longer than zero and shorter than 20 cm.The height can be anything taller than zero and shorter than 10 cm.
Area of square = (length of side)2 = (10cm)2 = 10*10 cm2 = 100 cm2
It is: 10*10*10 = 1000 cubic cm
40 cm (10cm x 4 sides = 40cm)
The area of a rectangle of sides 9cm and 10cm is:9cm x 10cm = 90cm2This is equivalent to 0.009m2
A triangle has 3 sides.
40cm (4 x 10 = 40)