No, it is not possible to draw a triangle with sides of 150 cm, 10 cm, and 10 cm. According to the triangle inequality theorem, the sum of the lengths of any two sides must be greater than the length of the third side. In this case, 10 cm + 10 cm is not greater than 150 cm.
No because the 3 sides of an equilateral triangle are equal in length
no because a²+b ²=c ². Because 10²+10²=14.1 100+100=200 So you can't have 150 but you can have 200
no because a²+b ²=c ². Because 10²+10²=14.1 100+100=200 So you can't have 150 but you can have 200
So?
It is a right angle triangle and its largest angle is 90 degrees
if it is a scalene triangle yes scalene triangle have no congruent sides and angles
No because the 3 sides of an equilateral triangle are equal in length
no because a²+b ²=c ². Because 10²+10²=14.1 100+100=200 So you can't have 150 but you can have 200
no because a²+b ²=c ². Because 10²+10²=14.1 100+100=200 So you can't have 150 but you can have 200
So?
150cm = 15dm There are 10cm in a decimeter.
Size or internal angles?
If the sides are 10cm, 17cm and 21cm, the three angles are approx 28, 53 and 99 degrees. It is an obtuse angled triangle.
It is a right angle triangle and its largest angle is 90 degrees
200 sq. cm.
one side equals 5 another equals 4 and the last is 1 (a=bh/2)
a is one of the equal sides of the iscosceles triangle b is the base perimeter is a + a + b = 46cm a = b + 5cm subsitute a for b + 5cm in the perimeter equation b + 5cm + b + 5cm + b = 46cm This simplifies down to 3b + 10cm = 46cm subtract 10cm from both sides of the equation 3b + 10cm - 10cm = 46cm - 10cm 3b = 36cm Then divide each side of the equation by 3 3b ÷ 3 = 36cm ÷ 3 b = 12cm Subsitute b back into a = b +5cm a = 12cm + 5cm a = 17cm So you have 2 sided with the length of 17cm and the base with the length of 12cm