No, it is not possible to draw a triangle with sides of 150 cm, 10 cm, and 10 cm. According to the triangle inequality theorem, the sum of the lengths of any two sides must be greater than the length of the third side. In this case, 10 cm + 10 cm is not greater than 150 cm.
No because the 3 sides of an equilateral triangle are equal in length
no because a²+b ²=c ². Because 10²+10²=14.1 100+100=200 So you can't have 150 but you can have 200
no because a²+b ²=c ². Because 10²+10²=14.1 100+100=200 So you can't have 150 but you can have 200
So?
It is a right angle triangle and its largest angle is 90 degrees
if it is a scalene triangle yes scalene triangle have no congruent sides and angles
No because the 3 sides of an equilateral triangle are equal in length
no because a²+b ²=c ². Because 10²+10²=14.1 100+100=200 So you can't have 150 but you can have 200
no because a²+b ²=c ². Because 10²+10²=14.1 100+100=200 So you can't have 150 but you can have 200
So?
150cm = 15dm There are 10cm in a decimeter.
Size or internal angles?
If the sides are 10cm, 17cm and 21cm, the three angles are approx 28, 53 and 99 degrees. It is an obtuse angled triangle.
It is a right angle triangle and its largest angle is 90 degrees
No, you cannot wrap a 15cm by 10cm by 10cm box using a single sheet of A4 paper. An A4 sheet measures 21cm by 29.7cm, which is not large enough to cover the surface area of the box completely. The surface area of the box is 2(15cm × 10cm + 10cm × 10cm + 15cm × 10cm) = 2(150cm² + 100cm² + 150cm²) = 2(400cm²) = 800cm², while an A4 sheet provides a limited area of 623.7cm².
200 sq. cm.
one side equals 5 another equals 4 and the last is 1 (a=bh/2)