Of course. The wavelength and amplitude have no influence on each other.
Speed = (wavelength) x (frequency) = (2 x 6) = 12 meters per second.That's the wave's speed. "Velocity" is something different, not just a wordto use when you mean "speed" but you want to sound more technical.
I'm going to assume that you're talking about the two familiar types of identificationof radio stations ... their frequency stated in megahertz, and their wavelength statedin meters. (If that's not what you're talking about, then the question is absurd.)The relationship may be a bit more complicated than what you're expecting:Wavelength (in meters) = 300 / frequency (in megahertz)Frequency (in megahertz) = 300 / wavelength (in meters)
12 meters is 9.36% longer than 12 yd. (rounded)
Several of them. Wavelength = speed of light/Hertz Wavelength = Planck's constant/mass of particle*Hertz And a few more that can be manipulated to find wavelength that I will let you discover on your own.
Meters
To convert frequency to wavelength, you can use the formula: wavelength = speed of light / frequency. The speed of light in a vacuum is approximately 3.00 x 10^8 meters per second. Dividing this speed by the frequency in hertz will give you the corresponding wavelength in meters.
It is a deep-water wave because the depth of the water is more than half the wavelength of the wave. In deep-water waves, the water depth is greater than half the wavelength.
Speed = (wavelength) x (frequency) = (2 x 6) = 12 meters per second.That's the wave's speed. "Velocity" is something different, not just a wordto use when you mean "speed" but you want to sound more technical.
The frequency of blue light with a wavelength of 4000 angstroms can be calculated using the formula: Frequency = speed of light (3.00 x 10^8 m/s) / wavelength (in meters). First, convert the wavelength from angstroms to meters (1 angstrom = 1 x 10^-10 meters), then plug the values into the formula to find the frequency.
An impala can jump more than 9 meters and 2.5 meters high.
The energy of an electromagnetic wave is directly proportional to its frequency. This relationship is described by Planck's equation E=hf, where E is the energy of the wave, h is Planck's constant, and f is the frequency. This means that as the frequency of the wave increases, so does its energy.
I'm going to assume that you're talking about the two familiar types of identificationof radio stations ... their frequency stated in megahertz, and their wavelength statedin meters. (If that's not what you're talking about, then the question is absurd.)The relationship may be a bit more complicated than what you're expecting:Wavelength (in meters) = 300 / frequency (in megahertz)Frequency (in megahertz) = 300 / wavelength (in meters)
Both a wave with long wavelength and a wave with short wavelength can have a lot of energy, or little energy.Specifically in the case of electromagnetic waves, a short wavelength corresponds to high energy - but this is only the energy PER PHOTON. But note that each of such waves usually consists of a lot of photons.
If you dip your finger more frequently, the wavelength of the waves will decrease. This is because the frequency of the waves (how often you dip your finger) is directly related to their wavelength - higher frequency results in shorter wavelengths.
A high energy light will have a shorter wavelength than a low energy light. If the wavelength goes down, then the frequency goes up. When calculating energy in the equation, E=hv, frequency (v) is the variable, not the wavelength. So in the equation, if you wanted a more energy (E), you would have the frequency be large. For the frequency to be big, then the wavelength has to be low.
The wave with a shorter wavelength will transmit more energy, because energy is directly proportional to frequency (which is inversely proportional to wavelength). So, a shorter wavelength corresponds to a higher frequency and thus more energy.
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