No, crocodiles do not typically reach lengths of 35 feet. The largest species, the saltwater crocodile, can grow up to around 23 feet (7 meters) in length, with the largest recorded individuals being slightly over that. While there are anecdotal reports of exceptionally large crocodiles, verified measurements rarely exceed 20 feet. Therefore, a length of 35 feet is highly improbable for any crocodile species.
To find the perimeter of a rectangle, you can use the formula ( P = 2(length + width) ). For a rectangle with a length of 35 feet and a width of 30 feet, the perimeter would be ( P = 2(35 + 30) = 2(65) = 130 ) feet. Therefore, the perimeter of the rectangle is 130 feet.
35 sq yds
Anything from the smallest possible width to just under 35 feet. ie 0<width<35 feet
7 ft *5 ft = 35 square feet.
To find the actual length of the train, we can set up a proportion based on the scale. The model train is 35 inches long, and according to the scale, 7 inches corresponds to 90 feet. Therefore, we can calculate the actual length as follows: [ \text{Actual Length} = \left( \frac{90 , \text{feet}}{7 , \text{inches}} \right) \times 35 , \text{inches} = 450 , \text{feet}. ] Thus, the actual length of the train is 450 feet.
The length of the other leg is 60.62 feet.
The room has an area of: 1,680 square feet (48 x 35 = 1,680).
1750. An rectangular area can be calculated simply by multiplying the length of one side by the length of an adjacent side, or length X width. In this case, 50 X 35 = 1,750.
To find the area of a room that is 35 feet by 35 feet, you would multiply the length by the width. So, 35 feet x 35 feet = 1225 square feet. Therefore, a room that is 35 feet by 35 feet has an area of 1225 square feet.
The length is 7 feet and the width is 5 feet
To find the perimeter of a rectangle, you can use the formula ( P = 2(length + width) ). For a rectangle with a length of 35 feet and a width of 30 feet, the perimeter would be ( P = 2(35 + 30) = 2(65) = 130 ) feet. Therefore, the perimeter of the rectangle is 130 feet.
35 sq yds
35-40 ft
If the yard is measured in square feet, then 35 feet times 48 feet equals 1680 square feet.
Anything from the smallest possible width to just under 35 feet. ie 0<width<35 feet
Multiply length times width; 35 x 8 = 280 square feet.
To find the area in square feet, multiply the length by the width. For 35 x 20, the calculation is 35 multiplied by 20, which equals 700. So, the area is 700 square feet.