To find the actual length of the train, we can set up a proportion based on the scale. The model train is 35 inches long, and according to the scale, 7 inches corresponds to 90 feet. Therefore, we can calculate the actual length as follows:
[ \text{Actual Length} = \left( \frac{90 , \text{feet}}{7 , \text{inches}} \right) \times 35 , \text{inches} = 450 , \text{feet}. ]
Thus, the actual length of the train is 450 feet.
To find the actual length of the fence, multiply the length on the blueprint by the scale. Given a scale of 1:40 and a length of 6 inches on the blueprint, the calculation would be 6 inches × 40 = 240 inches. Therefore, the actual length of the fence is 240 inches, or 20 feet.
To find the scale factor of the drawing, first convert the actual length from feet to inches since the drawing's length is in inches. There are 12 inches in a foot, so 8 feet equals 96 inches. The scale factor can then be calculated by dividing the drawing length (4 inches) by the actual length (96 inches), resulting in a scale factor of 1:24. This means that 1 inch on the drawing represents 24 inches in reality.
To determine the length of the object in the drawing, use the scale of 3 inches for every 4 feet. First, find the ratio of the actual length to the scale length: ( 24 \text{ ft} \div 4 \text{ ft} = 6 ). Then, multiply this ratio by the scale length: ( 6 \times 3 \text{ in} = 18 \text{ in} ). Therefore, the length of the object in the drawing is 18 inches.
To find the wingspan of Raul's scale model, divide the actual wingspan of 44 feet by the scale factor of 116116. Calculating this gives approximately 0.000379 feet, which is about 0.00455 inches, a very small model size.
1450ft
Fg
To find the actual length of the fence, multiply the length on the blueprint by the scale. Given a scale of 1:40 and a length of 6 inches on the blueprint, the calculation would be 6 inches × 40 = 240 inches. Therefore, the actual length of the fence is 240 inches, or 20 feet.
12 inches
To find the scale factor of the drawing, first convert the actual length from feet to inches since the drawing's length is in inches. There are 12 inches in a foot, so 8 feet equals 96 inches. The scale factor can then be calculated by dividing the drawing length (4 inches) by the actual length (96 inches), resulting in a scale factor of 1:24. This means that 1 inch on the drawing represents 24 inches in reality.
Scale
To find the scale of the blueprint, divide the actual length of the wall by the length on the blueprint. The actual length is 15 feet, which is equivalent to 180 inches (since 1 foot = 12 inches). The blueprint length is 5 centimeters, which is approximately 1.97 inches (since 1 centimeter ≈ 0.3937 inches). Therefore, the scale of the blueprint is 180 inches / 1.97 inches, which simplifies to approximately 91.4:1.
4418 by the power of 2
The scale factor for a model train with a length 36 inches and the length of engine itself is 24 feet would be 1/8th. In order to answer this you will have to do a little math.
To determine the length of the object in the drawing, use the scale of 3 inches for every 4 feet. First, find the ratio of the actual length to the scale length: ( 24 \text{ ft} \div 4 \text{ ft} = 6 ). Then, multiply this ratio by the scale length: ( 6 \times 3 \text{ in} = 18 \text{ in} ). Therefore, the length of the object in the drawing is 18 inches.
120 times 6 = 720 inches.
33 inches
Multiply 3.6 inches by 4 = 14.4 inches. Since this does not make any sense, the scale must be wrong or the car is meant to be driven by Lilliputians. Are you sure that the scale is not 40 to 1 or four feet to one inch or something else?