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1450ft
i dont know
Multiply it by the scale factor. For example 1:10 scale on length can be scaled up by multiplying the model length by 10. 2.3mm on the model will be 23mm in real life.
One inch on the model represents 72 inches -- or six feet -- on the real McCoy. Since the miniature is two inches long, the actual airplane it represents is 12 feet long.
62.5
Fg
12 inches
Scale
4418 by the power of 2
The scale factor for a model train with a length 36 inches and the length of engine itself is 24 feet would be 1/8th. In order to answer this you will have to do a little math.
120 times 6 = 720 inches.
33 inches
Multiply 3.6 inches by 4 = 14.4 inches. Since this does not make any sense, the scale must be wrong or the car is meant to be driven by Lilliputians. Are you sure that the scale is not 40 to 1 or four feet to one inch or something else?
a scale
When it is a scale model the model is proportional to the actual object only much smaller.
1450ft
To find the length of the park on the map, you can use the scale factor. The scale factor is calculated by dividing the actual length by the corresponding length on the map. In this case, the actual length is 9.1 miles and the width on the map is 2.13 inches. So, the length on the map would be 9.1 / 6.5 * 2.13 = 2.97 inches.