On a three dimensional basis yes it can.
Fir instance, if an object is moving directly towards or away from you the angular displacement can be zero though the distance displacement changes.
The question is incomplete. There is an if clause but no then clause.
No combination of non-zero even numbers can be relatively prime.
Divide a non-zero integer by a non-zero integer.
The absolute number, or absolute value, of a real number is defined as its distance from zero on the number line, regardless of its direction. Since distance cannot be negative, the absolute value is always a non-negative quantity. For any real number ( x ), the absolute value is expressed as ( |x| ), which yields a positive value or zero when ( x ) is zero. Thus, it is inherently designed to be non-negative.
A straight line with a constant slope
Yes, it is possible to have zero displacement and a non-zero average velocity. This can occur if an object moves back and forth over a certain distance so that the total displacement is zero, but the average velocity is non-zero due to the object covering distance in both directions.
Yes, it is possible for displacement to be zero while distance is not. This can happen when an object moves in different directions and its total movement results in a non-zero distance, while the net change in position (displacement) from start to finish is zero.
Yes. If you end up where you started, your displacement is zero, but the distance you travel is the actual amount of ground covered. For example, if you made a round trip of 50 miles, your displacement would be zero miles, but your distance would be 50 miles. This is because the final position and the initial position are the same. Round trips always have a displacement of zero.
Yes, displacement is how far are you from your original position. Therefore if you imagine walking around a circular path where you end up at the starting position, you've walked a certain distance however you havent been displaced (since your where you started).
When an object is propelled by a non-centripetal force through a closed path.
"Distance" covered is always greater than the magnitude of the displacement,unless the motion is in a straight line. In that case, distance and displacementare equal. Distance is never less than displacement.
i will give u an illustration, consider an object projected (thrown)with some initial vertical velocity from the ground such that it traces a open downward parabolicpath, in that path the vertical displacement of the body from the point of projection to the point where it strikes the ground is equal to zero,but it have some velocity.
No, a radio controlled car would not have an average velocity of zero if it moves in a straight line. Average velocity is the total displacement divided by the total time, so as long as the car moves, it will have a non-zero average velocity.
The question is incomplete. There is an if clause but no then clause.
Yes it is possible. Any body that travels in any particular closed shape (circle, square, triangle etc.) and returns to the point in which it started would have travelled a certain distance but the sum of its displacement would be nil. Example: A body travels in a 1 mile north, then 1 mile west, then one mile south and finally 1 mile east (ie. a square). The body has travelled a distance of 4 miles. The bodys displacement is 0 miles due to it returning to the point in which it started. You can calculate displacement using vectors. For this example assuming east is positive x and north is positive y: north + west + south + east y -x -y +x = 0
the displacement mean the shortest distance between two points. the shape of displacement where the objects move and its also help us to tell the shape of displacement with the use of graph.
even, whole, non-negative numbers. (zero is not a natural number)