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The sum of the ages of Art and Ben and Cal is 59. Art is 1 year older than Cal and Cal is 1 year younger than Ben. WhoIf anyone was a teenager 7 years ago?
Call the ages of the stated persons by the first letter of their names. From the second sentence of the problem statement, A = 1 + C and B = 1 + C. Substituting these values into the sum given in the first sentence of the problem statement yields 1 + C + 1 + C + C = 59, or C = (59 - 2)/3 = 19, A is 20, and B is 20. Seven years ago, C was 12 but A and B were both 13 and therefore were teenagers, but C was not.
Maria keeps her four stuffed bears lined up on a shelf over her bed how many arrangements of the bears are possible?
The answer is 4! (4 factorial), the same as 4x3x2x1, which equals 24 combinations. The answer is 24 and this is how: A b c d A b d c A c d b A c b d A d c b A d b c B c d a B c a d B d a c B d c a B a c d B a d c C d a b C d b a C a b d C a d b C b d a C b a d D a b c D a c b D b c a D b a c D c a b D c b a
What is b plus b plus b plus c plus c plus c plus c?
b+b+b+c+c+c+c =3b+4c
What is the negation of B is not between A and C?
The negation of B is not between A and C is = [(A < B < C) OR (C < B < A)] If A, B and C are numbers, then the above can be simplified to (B - A)*(C - B) > 0
Is it possible to use the associative property with subtraction?
No. There is a property of numbers called the distributive property that proves this wrong. a- ( b - c) is NOT the same as (a-b) -c because: a-(b-c) = a-b+c by the distributive property a-b+c = (a-b) + c by the definition of () (a-b)+c is not always equal to (a-b)-c
