When one draws an isosceles triangle and cast a line straight down from the top, It will result to a perpendicular bisector of the bottom leg. This will only work with an isosceles triangle.
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Yes.
The angle bisectors of a regular polygon are always concurrent. And the point that they meet at is also the meeting point of the perpendicular bisectors of the sides. If it is a polygon with an odd nmber of sides, the "medians" [line from vertex to mid-point of opposite side] and "altitudes" [perpendicular from vertex to opposite side] will also meet at the same point.
Equilateral triangles have 3 perpendicular bisectors
True, the diagonals of a rhombus are perpendicular bisectors of one another.
nope