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If I've read that correctly, you are asking if cube_root of all of x over 27 can be written in the form kx to the power p

ie ³√(x/27) = kx^p

Yes, with k = 1/3, p = 1/3

Cube root can be expressed as something to the power 1/3 since (x^a)^b = x^(ab) and cube roots are such that (³√x)³ = x and 1/3 × 3 = 1.

³√(x/27) = (x/27)^(1/3) = (x^(1/3))/(27^(1/3)) = (x^(1/3))/3 = (1/3)x^(1/3)

→ k = 1/3, p = 1/3.

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