As the number 1 is considered a special case and not a prime, there cannot be three consecutive numbers that are prime. Any three consecutive numbers must include at least one even number. With the exception of the number 2, no even numbers are prime.
0, 1, 2
2, 3Those two are consecutive, natural and prime numbers! It's as easy as one, two, three! (Pun intended)
8 has three primes (2x2x2) in its factorization, and 30 is the smallest number having three different primes (2x3x5) in its factorization.
It is a statement of numerical fact.
As the number 1 is considered a special case and not a prime, there cannot be three consecutive numbers that are prime. Any three consecutive numbers must include at least one even number. With the exception of the number 2, no even numbers are prime.
0, 1, 2
2, 3Those two are consecutive, natural and prime numbers! It's as easy as one, two, three! (Pun intended)
No. Every third consecutive natural number is divisible by 3.
8 has three primes (2x2x2) in its factorization, and 30 is the smallest number having three different primes (2x3x5) in its factorization.
It is a statement of numerical fact.
No. Any three consecutive numbers will have at least one of them which is divisible by 2, which means it cannot be prime. And since 1 is not considered a prime number, it cannot happen.
5711
If you take three consecutive odd (or three consecutive even) numbers, one of the three will always be a multiple of 3.If you take three consecutive odd (or three consecutive even) numbers, one of the three will always be a multiple of 3.If you take three consecutive odd (or three consecutive even) numbers, one of the three will always be a multiple of 3.If you take three consecutive odd (or three consecutive even) numbers, one of the three will always be a multiple of 3.
There is only one pair of consecutive prime numbers, and the prime numbers are two and three, because any pair of consecutive numbers has one odd and one even number, and two is the only even prime number, because all other even numbers can be divided by two, and the only pairs of consecutive numbers are one and two and three, but one is not prime because it only has one factor, thus making the only consecutive pair of primes two and three. But the problem asks for the product of the two numbers, not the numbers themselves, so just multiply two and three together to get a final result of six.
There are no three consecutive numbers with a sum of 170.
There are no sets of three consecutive numbers totaling 118.