A square will. The only shape that can enclose more area with the same perimeter is a circle.
Most shapes have different perimeter than area, as far as value.
a square
Because the area is different than the perimeters
That two different shapes may well have the same perimeter, but different areas. As an example, a 3 x 1 rectangle and a 2 x 2 rectangle have the same perimeter, but the area is different.
A square will. The only shape that can enclose more area with the same perimeter is a circle.
Most shapes have different perimeter than area, as far as value.
a square
yes they can
Because the area is different than the perimeters
That two different shapes may well have the same perimeter, but different areas. As an example, a 3 x 1 rectangle and a 2 x 2 rectangle have the same perimeter, but the area is different.
Most shapes can have the same area and different perimeters. For example the right size square and circle will have the same are but they will have different perimeters. You can draw an infinite number of triangles with the same area but different perimeters. This is before we think about all the other shapes out there.
You can't. The perimeter doesn't tell the area. There are an infinite number of shapes with different dimensions and different areas that all have the same perimeter.
no
You can't. The perimeter doesn't tell the area. There are an infinite number of shapes with different dimensions and different areas that all have the same perimeter.
No, two rectangles with the same area do not necessarily have the same perimeter. For example, a rectangle with dimensions 2 x 6 has an area of 12 and a perimeter of 16, while a rectangle with dimensions 3 x 4 also has an area of 12 but a perimeter of 14. Thus, different combinations of length and width can yield the same area but different perimeters.
the area of a rectangleis 100 square inches. The perimeter of the rectangle is 40 inches. A second rectangle has the same area but a different perimeter. Is the secind rectangle a square? Explain why or why not.