Yes, ( x - 5 ) can be a remainder when dividing a polynomial ( p(x) ) by ( 7x^2 ). According to the polynomial remainder theorem, the remainder of a polynomial division by a polynomial of degree ( n ) will have a degree less than ( n ). Since ( 7x^2 ) is a polynomial of degree 2, the remainder can be of degree 1 or less, which means it can indeed be of the form ( x - 5 ).
The expression (x - 5) is a factor of the polynomial (2x^2 - 7x - 15) if substituting (x = 5) yields a result of zero for the polynomial. To determine this, we can use polynomial long division or synthetic division. If (2x^2 - 7x - 15) can be divided by (x - 5) without a remainder, then (x - 5) is indeed a factor of the polynomial. Otherwise, it is not a factor.
To find the remainder when the polynomial (-3x^2 + 7x - 9) is divided by (x - 2) using synthetic division, we use the value (2). Setting up synthetic division, we have: [ \begin{array}{r|rrr} 2 & -3 & 7 & -9 \ & & -6 & 2 \ \hline & -3 & 1 & -7 \ \end{array} ] The final value, (-7), is the remainder. Therefore, the remainder when dividing (-3x^2 + 7x - 9) by (x - 2) is (-7).
To divide the polynomial (14x^3 - 45x^2 - 28x - 4) by (7x + 2), we can use polynomial long division. Performing the division yields a quotient of (2x^2 - 9x - 2) with a remainder of (-18). So, the result is (2x^2 - 9x - 2 - \frac{18}{7x + 2}).
To divide the polynomial (2x^2 + 7x + 5) by a linear polynomial, you typically use polynomial long division or synthetic division. However, since you didn't specify a divisor, I'll assume you're asking for the quotient of (2x^2 + 7x + 5) divided by (1), which is simply the polynomial itself: (2x^2 + 7x + 5). If you meant a different divisor, please specify for a more accurate answer.
The degree of a polynomial is determined by the highest exponent of the variable in the expression. In the polynomial (7x^5), the highest exponent of (x) is 5. Therefore, the degree of the polynomial (7x^5) is 5.
The expression (x - 5) is a factor of the polynomial (2x^2 - 7x - 15) if substituting (x = 5) yields a result of zero for the polynomial. To determine this, we can use polynomial long division or synthetic division. If (2x^2 - 7x - 15) can be divided by (x - 5) without a remainder, then (x - 5) is indeed a factor of the polynomial. Otherwise, it is not a factor.
To find the remainder when the polynomial (-3x^2 + 7x - 9) is divided by (x - 2) using synthetic division, we use the value (2). Setting up synthetic division, we have: [ \begin{array}{r|rrr} 2 & -3 & 7 & -9 \ & & -6 & 2 \ \hline & -3 & 1 & -7 \ \end{array} ] The final value, (-7), is the remainder. Therefore, the remainder when dividing (-3x^2 + 7x - 9) by (x - 2) is (-7).
To divide the polynomial (14x^3 - 45x^2 - 28x - 4) by (7x + 2), we can use polynomial long division. Performing the division yields a quotient of (2x^2 - 9x - 2) with a remainder of (-18). So, the result is (2x^2 - 9x - 2 - \frac{18}{7x + 2}).
-6
-7
To divide the polynomial (2x^2 + 7x + 5) by a linear polynomial, you typically use polynomial long division or synthetic division. However, since you didn't specify a divisor, I'll assume you're asking for the quotient of (2x^2 + 7x + 5) divided by (1), which is simply the polynomial itself: (2x^2 + 7x + 5). If you meant a different divisor, please specify for a more accurate answer.
Oh, what a happy little question! Let's gently divide 2 into the polynomial -3x^2 + 7x - 9. When we do that, we find that the remainder is -6x - 21. Just remember, there are no mistakes, only happy little accidents in math!
The degree of a polynomial is determined by the highest exponent of the variable in the expression. In the polynomial (7x^5), the highest exponent of (x) is 5. Therefore, the degree of the polynomial (7x^5) is 5.
I am assuming this is: .2x4 - 5x2 - 7x, which would be a Quartic Polynomial.
It's just a mathematical polynomial: 7x + 3y.
True.
3(7x-6)