-6
x3 - 2x2 + x - 2 =(x - 2)(x2 + 1)
Well, 4 is 2X2 and 6 is 2X3 so the number needs two 2s and one 3 :2x2x3=12
Multiply x3 - 2x2 - 13x - 10
Divide all terms by 3:- 2x2+5x-3 = (2x-1)(x+3) when factored
2x3 + 8x2 + 3x + 12 = (2x3 + 8x2) + (3x + 12) = 2x2(x + 4) + 3(x + 4) = (x + 4)(2x2 + 3) Since you have asked this question I am assuming that you are not yet at a level where you might want (2x2 + 3) factorised into its imaginary factors.
2x2-4x+5 divided by x-1 Quotient: 2x-2 Remainder: 3
A quadratic polynomial.
yes
A Quadratic statement
quadratic
The discriminant is -7
2x2-3x-5 = (2x-5)(x+1) when factored
Remainder Theorem:- When f(x) is divided by (x-a) the remainder is f(a) Tor example:- f(x) x3-2x2+5x+8 divided by x-2 f(2) 8-8+10+8 = 18 So the remainder is 18 if there is no remainder then the divisor is a factor of the dividend.
The discriminant is 88.
x3 - 2x2 + x - 2 =(x - 2)(x2 + 1)
65
88 -Apex ;)