The answer depends on what group or field the function is defined on. In the complex plane, the range is the complex plane. If the domain is all real numbers and the radical is an odd root (cube root, fifth root etc), the range is the real numbers. Otherwise, it is the complex plane. If the domain is non-negative real numbers, the range is also the real numbers.
It helps to visualize the numbers on a plane. The complex numbers occupy the entire plane. The real numbers are all the numbers on the horizontal axis, the imaginary numbers are all the numbers on the vertical axis. A complex number thus has a real and an imaginary part, a + bi, where a and be are real numbers (for example, 3 - 2i).
I will evaluate all my math homework.
You can draw a triangle on the complex plane, but all of the distances (side lengths) are considered 'real' distances {just like the magnitudes of individual complex numbers}. So I believe the answer is No.
The Julia can be generated by a quadratic equation in the complex plane. Select a complex number c. Then for a point z in the plane, carry out the iteration, zn+1 = zn2 + c. Colour-code the point according to how many iterations are required before its magnitude exceeds any given threshold. Repeat for all z in the region of the plane.
All complex numbers are part of the "complex plane", so none of them is farther than others.
Always. The set of imaginary numbers is a subset of complex numbers. Think of complex numbers as a plane (2 dimensional). The real numbers exist on the horizontal axis. The pure imaginary are the vertical axis. All other points on the plane are combinations of real and imaginary. All points on the plane (including imaginary axis and real axis) are complex numbers.
INTEGRATION
Evaluate means put numbers into a formula to see what the resulting value is. It does not matter what these numbers are: real, imaginary, complex, integers, etc, they are all treated as just values being substituted.
The answer depends on what group or field the function is defined on. In the complex plane, the range is the complex plane. If the domain is all real numbers and the radical is an odd root (cube root, fifth root etc), the range is the real numbers. Otherwise, it is the complex plane. If the domain is non-negative real numbers, the range is also the real numbers.
If t is real then [1 to infinity) ie all real numbers from 1 to infinity, including 1 but not infinity. If t is in the complex plane then the domain of t^2+1 is also the complex plane.
It helps to visualize the numbers on a plane. The complex numbers occupy the entire plane. The real numbers are all the numbers on the horizontal axis, the imaginary numbers are all the numbers on the vertical axis. A complex number thus has a real and an imaginary part, a + bi, where a and be are real numbers (for example, 3 - 2i).
I will evaluate all my math homework.
You can draw a triangle on the complex plane, but all of the distances (side lengths) are considered 'real' distances {just like the magnitudes of individual complex numbers}. So I believe the answer is No.
The Julia can be generated by a quadratic equation in the complex plane. Select a complex number c. Then for a point z in the plane, carry out the iteration, zn+1 = zn2 + c. Colour-code the point according to how many iterations are required before its magnitude exceeds any given threshold. Repeat for all z in the region of the plane.
The set of real numbers are a subset of the set of complex numbers: imagine the complex plane with real numbers existing on the horizontal number line, and pure imaginary existing on the vertical axis. The entire plane (which includes both axes) is the set of complex numbers. So any real number (such as pi) will also be a complex number. But many people think of complex numbers as something that is "not a real number".
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