x^2 - 6x + 18.
This looks tempting to factor by guessing.
We want to factor into the form (1x + a) * (1x + b) + c
We guess that both x's have a scalar constant of 1, because x^2 has a scalar constant of 1 in the expanded form. This doesn't have to be the case, but it is a convenient assumption to make.
We want a and b such that (a + b) = -6.
A good choice for this is a = -3, b = -3
a * b = 9, so we need c to cover the distance between 9 and 18. c = 9
So we have:
(x - 3) * (x - 3) + 9
Double checking to make sure we did everything right:
x ^ 2 - 3x - 3x + 9 + 9
x^2 - 6x + 18
You can also complete the square, if you prefer.
3
Since the problem has 4 terms, first you factor x cubed plus 9x squared, then you factor 2x plus 18. So when you factor the first two term, you would get x sqaured (x plus 9). Then when you factor the last two terms and you get 2 (x plus 9). Ypure final answer would be (x squared plus 2)(x plus 9)
As written, that's 12a + 18 which factors to 6(2a + 3) a^2 + 11a + 18 = (a + 9)(a + 2)
-((x + 2)(x - 9))
x^2-9x+18=(x-6)(x-3)
6(w + 3)
3
I'm not sure this was notated correctly. As written, this is -11x plus or minus 18, which doesn't factor.
No, a factor cannot be larger than the numbers it is compared to.
Since the problem has 4 terms, first you factor x cubed plus 9x squared, then you factor 2x plus 18. So when you factor the first two term, you would get x sqaured (x plus 9). Then when you factor the last two terms and you get 2 (x plus 9). Ypure final answer would be (x squared plus 2)(x plus 9)
(x^18 - 6x^9 + 18)(x^18 + 6x^9 + 18)
As written, that's 12a + 18 which factors to 6(2a + 3) a^2 + 11a + 18 = (a + 9)(a + 2)
-((x + 2)(x - 9))
You take out the common factor, 6. 6y + 18 = 6(y + 3)
The GCF is 6.
4x + 27x + 18 = 0 31x + 18= 0 31x + 18 - 18= 0 - 18 31x = -18 31x / 31 = -18 / 31 x = -.58
5x squared plus 33x plus 18 = (5x + 3)(x + 6) x = -6, -3/5