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3x6 =18 and 7-5=2. Now 18x2=36
6 x 6 = 36 1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 = 36
1 yd = 36 in 6 yd 5 in - 2 yd 7 in = (5 + 1) yd 5 in - 2 yd 7 in = 5 yd (36 + 5) in - 2 yd 7 in = (5-2) yd (36 + 5 - 7) in = 3 yd 34 in.
36/7 Im reading (7+5)/ (9- 6 +2/3) correct?
On two 6-sided fair dice:Rolling a sum of 5: 4 out of 36, or 11.11%Rolling a sum of 7: 6 out of 36, or 16.67%Rolling a sum of either 5 or 7: 10 out of 36, or 27.78%Here's why: Look at the dice as unique, (maybe one is red and one is blue). Then there are 36 different possible outcomes.The four that give a sum of 5: 1+4, 2+3, 3+2, 4+1.The six that give sum of 7: 1+6, 2+5, 3+4, 4+3, 5+2, 6+1So there are 4 chances out of 36 (or 1 out of 9 = 11.11%) to get a sum of 5, and 6 chances out of 36 (or 1 out of 6 = 16.67%) to get a sum of 7. If you want either 5 or 7 as a sum, add the chances together to get 10 out of 36 (or 5 out of 18 = 27.78%)