3x6 =18 and 7-5=2. Now 18x2=36
6 x 6 = 36 1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 = 36
1 yd = 36 in 6 yd 5 in - 2 yd 7 in = (5 + 1) yd 5 in - 2 yd 7 in = 5 yd (36 + 5) in - 2 yd 7 in = (5-2) yd (36 + 5 - 7) in = 3 yd 34 in.
On two 6-sided fair dice:Rolling a sum of 5: 4 out of 36, or 11.11%Rolling a sum of 7: 6 out of 36, or 16.67%Rolling a sum of either 5 or 7: 10 out of 36, or 27.78%Here's why: Look at the dice as unique, (maybe one is red and one is blue). Then there are 36 different possible outcomes.The four that give a sum of 5: 1+4, 2+3, 3+2, 4+1.The six that give sum of 7: 1+6, 2+5, 3+4, 4+3, 5+2, 6+1So there are 4 chances out of 36 (or 1 out of 9 = 11.11%) to get a sum of 5, and 6 chances out of 36 (or 1 out of 6 = 16.67%) to get a sum of 7. If you want either 5 or 7 as a sum, add the chances together to get 10 out of 36 (or 5 out of 18 = 27.78%)
36/7 Im reading (7+5)/ (9- 6 +2/3) correct?
3x6 =18 and 7-5=2. Now 18x2=36
6 x 6 = 36 1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 = 36
When two dice are rolled, the probability of getting: 2 is 1/36 3 is 2/36 4 is 3/36 5 is 4/36 6 is 5/36 7 is 6/36 8 is 5/36 9 is 4/36 10 is 3/36 11 is 2/36 12 is 1/36
1 yd = 36 in 6 yd 5 in - 2 yd 7 in = (5 + 1) yd 5 in - 2 yd 7 in = 5 yd (36 + 5) in - 2 yd 7 in = (5-2) yd (36 + 5 - 7) in = 3 yd 34 in.
6^(7-5) = 36
On two 6-sided fair dice:Rolling a sum of 5: 4 out of 36, or 11.11%Rolling a sum of 7: 6 out of 36, or 16.67%Rolling a sum of either 5 or 7: 10 out of 36, or 27.78%Here's why: Look at the dice as unique, (maybe one is red and one is blue). Then there are 36 different possible outcomes.The four that give a sum of 5: 1+4, 2+3, 3+2, 4+1.The six that give sum of 7: 1+6, 2+5, 3+4, 4+3, 5+2, 6+1So there are 4 chances out of 36 (or 1 out of 9 = 11.11%) to get a sum of 5, and 6 chances out of 36 (or 1 out of 6 = 16.67%) to get a sum of 7. If you want either 5 or 7 as a sum, add the chances together to get 10 out of 36 (or 5 out of 18 = 27.78%)
36/7 Im reading (7+5)/ (9- 6 +2/3) correct?
There are 36 permutations of two dice. Of them, 6 have a sum of 7, (1+6, 2+5, 3+4, 4+3, 5+2, and 6+1) and 2 have a sum of 11 (5+6 and 6+5). The probability, then of getting a sum of 7 or 11 is (6 plus 2) in 36, or 8 in 36, or 2 in 9, or about 0.2222.
Probability of rolling a 3 is 2/36 & the probability of rolling a 6 is 5/36; probability of rolling a 3 or 5 is 2/36 + 5/36 = 7/36.
Each die has 6 outcomes: 1, 2, 3, 4, 5, 6. Total outcomes for 2 die is 6 * 6 = 36. You can easily write out the 36 outcomes; but the ones that add to 7 are: 1&6, 2&5, 3&4, 4&3, 5&2, and 6&1. Therefore, there are 6 ways to get a 7. So, 6 ways to get a 7: = 6/36 = 1/6.
712, 18, 24, 30, 36, 42, 48
11/3 x 36/7 = 396/21 = 132/7 or 18 and 6/7