3x6 =18 and 7-5=2. Now 18x2=36
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The probabilities of rolling specific numbers with 2 dice are as follows: 2: 1/36 3: 2/36 4: 3/36 5: 4/36 6: 5/36 7: 6/36 8: 5/36 9: 4/36 10: 3/36 11: 2/36 12: 1/36 Just add up the favorable probabilities in this case.
36/60 or 3/5
36+(18+12)/6 = 36+30/6 = 36+5 = 41
3
Sample space of the event = 6 x 6 = 36. The possible order for the set of numbers whose sum would be 8 are (2,6),(3,5),(4,4),(5,3),(6,2). There are five such sets. Therefore, Required probability = 5/36.