10 to the power of 7?
Wiki User
∙ 13y agoThe volume fraction of a substance is equal to the mole fraction for ideal gas mixture
because mole fraction doesnot depend on volume
You flip it to a fraction
An example is: 3/4 = 9/12
% to fraction: divide % by 100%Example: 3% = 3%/100% = 3/100fraction to 100%: multiply the fraction by 100%Example: 3/100 =3/100 * 100% = 3%
To find the mole fraction of oxygen, first convert the percentages to fractions: 37% oxygen is 0.37 and 63% nitrogen is 0.63. Since the total mole fraction in a mixture is 1, the mole fraction of oxygen would be 0.37/(0.37 + 0.63) = 0.37/1 = 0.37. Therefore, the mole fraction of oxygen in the gas mixture is 0.37.
For Ideal gases, mole fraction=volume fraction
The volume fraction of a substance is equal to the mole fraction for ideal gas mixture
because mole fraction doesnot depend on volume
The mole fraction of oxygen gas in air is approximately 0.21. This means that out of every 1 mole of air, 0.21 moles are oxygen gas molecules.
You flip it to a fraction
22/7
An example is: 3/4 = 9/12
In what situtation can you use only multiplication to find equivalent fraction? Give an example
You need the balanced symbol equation for the reaction. The numbers in front of the formulae show the mole ratios. For example, in the thermal decomposition of calcium carbonate: CaCO3 --> CaO + CO2 The equation is balanced. The mole ratio between CaCO3 and CO2 is 1:1 because there is 1 mole of CaCO3 for every mole of CO2
Mole fraction is dimensionless. It's the amount of moles of species "A" divided by the total amount of moles in the mixture. So "mole A / mole total" equals "dimensionless". To add clarity in the use of mole fractions, one could add as "unit" mole A / mole "mixture".
First, calculate the moles of water: 175g / 18.0116 g/mol = 9.721 moles. The total moles in the solution is the sum of water and phosphoric acid (H3PO4) moles. Next, calculate the mole fraction of H3PO4: moles of H3PO4 / total moles in the solution. This will give you the mole fraction of phosphoric acid in the solution.