Here is one way:
(1 + 32)*(5-4)
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Use the following [Euro]cent coins: 10 + 5 + 1 10 + 2 + 2 + 2 10 + 2 + 2 + 1 + 1 10 + 2 + 1 + 1 + 1 + 1 10 + 1 + 1 + 1 + 1 + 1 +1 5 + 5 + 5 +1 5 + 5 + 2 + 2 + 2 etc.
They are: 12+32 = 10 or as 1+9 = 10
5, 2, 2 and 1.
Use any three numbers whose sum is 10.For example, 1/10 + 2/10 + 7/10 = 10/10 = 1 or 3/10 - 9/10 + 2/10 = 10/10 = 1
Convert the mixed number to an improper fraction, make the two fractions equivalent fractions with the same denominator, and compare the numerators: 1 1/2 = (1×2+1)/2 = 3/2 3/2 = (3×5)/(2×5) = 15/10 15 < 28 → 15/10 < 28/10 → 1½ < 28/10 → No; 1½ is not greater than 28/10