You cannot. If you know the volume, temperature and pressure of a pencil, you will be no closer to knowing its mass!
If you are given the volume, then you do not need to work it out!
The equation is P1V1=P2V2. (P1 is pressure before the change, P2 is the pressure after, V1 is the volume before the change, and V2 is the volume after it.) So to solve it, it would be the same change no matter how much the volume and pressure were to begin with. The values are P1= 1 atmosphere (the pressure of air at sea level) V1= 1 Liter which would mean P2=3 atmospheres 1*1=3(V2) 1/3 Liter= V2. So the volume would be one third of what it was before the pressure was tripled.
Work Done = Fs cos 0 OR- Work done by an expanding gas against a constant pressure would be w=F*d (Recall that F=PA; from P=F/A) W= (PA)d (volume = area*d) Therefore Work done = p (change in volume)
Gross volume is the volume at actual condition whereas standard volume is at standard Pressure/Temperature condition.
In the context of thermodynamics, work done on a gas can be calculated using the formula W = PΔV, where P is pressure and ΔV is the change in volume. Since work done is measured in joules, pressure multiplied by volume change gives the work done in joules.
Without actually doing your homework for you ... have you noticed that if you multiply pressure by volume you get the exact units used for work?
When the volume of a gas increases and its pressure decreases, the state of the gas is expanding. This typically occurs when the gas is allowed to do work by pushing against a piston, which results in an increase in volume and a decrease in pressure.
The product of pressure times volume is equal to the work done on a gas. This relationship is described by the ideal gas law equation, which states that pressure multiplied by volume equals the number of moles of gas, the gas constant, and the temperature of the gas.
When an ideal gas does positive work on its surroundings, its volume increases. This is because the gas is expanding against an external pressure, leading to an increase in volume while maintaining pressure and temperature constant.
The work done in an isobaric expansion is given by the formula: work = pressure x change in volume. This is because in an isobaric process, the pressure remains constant while the volume changes, resulting in work being done on or by the system.
The volume is constant. The pressure will increase.The volume is constant. The pressure will increase.
Shaft work refers to the work done on a system by a rotating shaft, such as a turbine or motor. Flow work, also known as pressure-volume work, is the work done by a fluid moving through a system due to changes in pressure or volume. Both are important concepts in thermodynamics for analyzing energy transfers.
The product of pressure and volume has the same SI base units as energy or work, which is measured in joules (J). This is due to the definition of pressure (P) as force per unit area (N/m^2) and volume (V) as cubic meters (m^3), where the units of pressure times volume results in joules (J).
You cannot stretch a gas. If you extend the volume in which some gas is enclosed you are working against the difference in between the external atmospheric pressure and the internal pressure of the gas. As you increase the enclosed volume, the pressure inside there falls and you have to work harder.
"When the pressure of a gas at constant temperature is increased, the volume of the gas decreases. When the pressure is decreased, the volume increases." More precisely, pressure is inversely proportional to volume.
Pressure and volume are inversely related in a system at constant temperature (Boyle's Law). As pressure increases, volume decreases and vice versa. This relationship is direct in the sense that an increase in pressure leads to a decrease in volume, and a decrease in pressure leads to an increase in volume.