Yes, the expression (5(D + 1)) can be rewritten as (5D + 5). This is achieved by applying the distributive property, multiplying (5) by both (D) and (1).
The expression ( 5(D + 1) ) represents five times the quantity of ( D ) plus one. To simplify, you can distribute the 5, resulting in ( 5D + 5 ). This shows that the expression scales both ( D ) and the constant by the factor of 5.
The distributive property states that a(b + c) = ab + ac. To use this to write an expression equivalent to ( x + y ), you can express it as ( 1(x + y) ), which simplifies to ( 1 \cdot x + 1 \cdot y ). Thus, applying the distributive property, you can rewrite ( x + y ) as ( 1 \cdot (x + y) ) or simply keep it as ( x + y ) since it remains equivalent.
The expression "1".
The expression ( \frac{7}{14} ) simplifies to ( \frac{1}{2} ). The quotient ( \frac{1}{2} ) is between the consecutive whole numbers 0 and 1.
17*9 = 17*(10-1) = 17*10 - 17*1 = 170 - 17People who do not know the 17 times table might find the equivalent version easier to evaluate.
1/25
To write one tenth of w in an algebraic expression, you can use the expression (1/10)w or w/10. Both of these expressions represent dividing w by 10, which is equivalent to finding one tenth of w.
5d-1=-11 5d=-11 + 1 5d=-10 d= -10/5 d=-2
15 1/2
Do you mean: 11d +1 = 5d+49? If so: 11d+1 = 5d+49 11d-5d = 49-1 6d = 48 d = 8
The expression ( 5(D + 1) ) represents five times the quantity of ( D ) plus one. To simplify, you can distribute the 5, resulting in ( 5D + 5 ). This shows that the expression scales both ( D ) and the constant by the factor of 5.
The expression "1".
-30/1
15 1/2
0.0156
2m + 1
The expression ( \frac{7}{14} ) simplifies to ( \frac{1}{2} ). The quotient ( \frac{1}{2} ) is between the consecutive whole numbers 0 and 1.