i am 12 and the answer is:
The vertex is: -5/8, 7/8
X intercepts are: -3/8 AND -12 7/8
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I believe the following answers will be found correct:
y = 8x2 + 10x + 3 = (4x + 3)(2x + 1).
The x-intercepts occur at x = -¾ and x = -½.
The vertex occurs at x = -5/8, y = (-5/2 + 3)(-5/4 + 1) = (1/2)(-1/4) = -1/8;
that is, at (-5/8, -1/8).
The parabola is, of course, concave-upwards.
The parabola
If x2 is negative it will have a maximum value If x2 is positive it will have a minimum value
The real solutions are the points at which the graph of the function crosses the x-axis. If the graph never crosses the x-axis, then the solutions are imaginary.
No. It can also be a circle, ellipse or hyperbola.
the graph for a quadratic equation ct5r
the graph of a quadratic function is a parabola. hope this helps xP
The zeros of a quadratic function, if they exist, are the values of the variable at which the graph crosses the horizontal axis.
Yes. And the question is ...
The parabola
If x2 is negative it will have a maximum value If x2 is positive it will have a minimum value
Some do and some don't. It's possible but not necessary.
No translation will invert a quadratic graph.
The real solutions are the points at which the graph of the function crosses the x-axis. If the graph never crosses the x-axis, then the solutions are imaginary.
Yes.
That the function is a quadratic expression.
A translation.
You may mean, what is the graph of the function y = x^2 + 3. This graph shows a upward parabola with a y-intercept of 3 and a minimum at x=0.