i am 12 and the answer is:
The vertex is: -5/8, 7/8
X intercepts are: -3/8 AND -12 7/8
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I believe the following answers will be found correct:
y = 8x2 + 10x + 3 = (4x + 3)(2x + 1).
The x-intercepts occur at x = -¾ and x = -½.
The vertex occurs at x = -5/8, y = (-5/2 + 3)(-5/4 + 1) = (1/2)(-1/4) = -1/8;
that is, at (-5/8, -1/8).
The parabola is, of course, concave-upwards.
The parabola
If x2 is negative it will have a maximum value If x2 is positive it will have a minimum value
To determine the quadratic function from a graph, first identify the shape of the parabola, which can open upwards or downwards. Look for key features such as the vertex, x-intercepts (roots), and y-intercept. The standard form of a quadratic function is ( f(x) = ax^2 + bx + c ), where ( a ) indicates the direction of the opening. By using the vertex and intercepts, you can derive the coefficients to write the specific equation of the quadratic function.
The real solutions are the points at which the graph of the function crosses the x-axis. If the graph never crosses the x-axis, then the solutions are imaginary.
No. It can also be a circle, ellipse or hyperbola.
the graph of a quadratic function is a parabola. hope this helps xP
The zeros of a quadratic function, if they exist, are the values of the variable at which the graph crosses the horizontal axis.
Yes. And the question is ...
The parabola
If x2 is negative it will have a maximum value If x2 is positive it will have a minimum value
To determine the quadratic function from a graph, first identify the shape of the parabola, which can open upwards or downwards. Look for key features such as the vertex, x-intercepts (roots), and y-intercept. The standard form of a quadratic function is ( f(x) = ax^2 + bx + c ), where ( a ) indicates the direction of the opening. By using the vertex and intercepts, you can derive the coefficients to write the specific equation of the quadratic function.
Some do and some don't. It's possible but not necessary.
No translation will invert a quadratic graph.
The real solutions are the points at which the graph of the function crosses the x-axis. If the graph never crosses the x-axis, then the solutions are imaginary.
Yes.
That the function is a quadratic expression.
You may mean, what is the graph of the function y = x^2 + 3. This graph shows a upward parabola with a y-intercept of 3 and a minimum at x=0.