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How do you get the answer 7 if you can only use the numbers 1 4 9 and 2?
9 - (4 - 2) * 1 = 7
What is the distance between the two points 7 7 and 4 3?
Use Pythagoras: distance = √(difference_in_x^2 + difference_in_y^2) = √((4 - 7)^2 + (3 - 7)^2) = √((-3)^2 + (-4)^2) = √(9 + 16) = √25 = 5 units.
What is 20-2n when n equals 7?
20-2n when n = 7. just take 20-2(7) replace n with 7. then use the PEMDAS rule. 2(7) = 14, then 20-14 = 6
What are the 2 numbers if the arithmetic mean is 7 and the geometric mean is 3?
(x+y)/2=7; x+y=14; y=14-x 3=√(xy); xy=9; y=9/x Use substitution: 14-x=9/x; 14x - x2=9; x2 - 14x +9=0 Use the quadratic formula: x=[14±√(196-36)]/2; x=[14±√160]/2; x=[14±4√10]/2 x=7+2√10 or x=7-2√10 If x=7+2√10, then y=14-(7+2√10)=7-2√10 If x=7-2√10, then y=14-(7-2√10)=7+2√10 The first pair's geometric mean is √[(7+2√10)(7-2√10)]=√[72-(2√10)2]=√(49-40)=√9=3. The first pair's arithmetic mean is (7+2√10 +7-2√10)/2=14/2=7 The second pair's geometric mean is √[(7-2√10)(7+2√10)]=√[72-(2√10)2]=√(49-40)=√9=3. The second pair's arithmetic mean is (7-2√10 +7+2√10)/2=14/2=7 That's it!
How can you use doubling to find the product of 4 times 7?
since 4 is 2 times 2 just double 7 twice: 7 doubled = 14 and then 14 double = 28
