It used 2.5
9 - (4 - 2) * 1 = 7
Use Pythagoras: distance = √(difference_in_x^2 + difference_in_y^2) = √((4 - 7)^2 + (3 - 7)^2) = √((-3)^2 + (-4)^2) = √(9 + 16) = √25 = 5 units.
To solve ((3x + 7)^2), you can use the formula for squaring a binomial, which is ((a + b)^2 = a^2 + 2ab + b^2). Here, (a = 3x) and (b = 7). Applying the formula gives: [ (3x + 7)^2 = (3x)^2 + 2(3x)(7) + 7^2 = 9x^2 + 42x + 49. ] So, ((3x + 7)^2 = 9x^2 + 42x + 49).
The prime factorization of 196 is (2^2 \times 7^2). However, to express 196 as a product of three prime numbers, you can use the primes 2, 7, and 7, since (2 \times 7 \times 7 = 196). Thus, the three prime numbers are 2, 7, and 7.
To find the product of (3p + 7)(3p + 7), you can use the formula for the square of a binomial, which is ( (a + b)^2 = a^2 + 2ab + b^2 ). In this case, ( a = 3p ) and ( b = 7 ). Therefore, the product is: [ (3p)^2 + 2(3p)(7) + 7^2 = 9p^2 + 42p + 49. ] So, the final result is ( 9p^2 + 42p + 49 ).
use the tens place to multiply by 2, then use the number to subtract the ones place.The answer can be divided by 7, if not it will be 0.use 490 as an example.9x2=18.18-4=14.14 divided by 7 is 2. so 49 can be divide by 7
9 - (4 - 2) * 1 = 7
Use the formula n(n-1)/2 --> 7(7-1)/2 = 7(6)/2 = 42/2 = 21.
7, 2 and 0
Use Pythagoras: distance = √(difference_in_x^2 + difference_in_y^2) = √((4 - 7)^2 + (3 - 7)^2) = √((-3)^2 + (-4)^2) = √(9 + 16) = √25 = 5 units.
To solve ((3x + 7)^2), you can use the formula for squaring a binomial, which is ((a + b)^2 = a^2 + 2ab + b^2). Here, (a = 3x) and (b = 7). Applying the formula gives: [ (3x + 7)^2 = (3x)^2 + 2(3x)(7) + 7^2 = 9x^2 + 42x + 49. ] So, ((3x + 7)^2 = 9x^2 + 42x + 49).
1 x 7 plus 2 x 7 is the same as 3 x 7
(6+7)x2=26... 26-(9-7)=24 !
The prime factorization of 196 is (2^2 \times 7^2). However, to express 196 as a product of three prime numbers, you can use the primes 2, 7, and 7, since (2 \times 7 \times 7 = 196). Thus, the three prime numbers are 2, 7, and 7.
To find the product of (3p + 7)(3p + 7), you can use the formula for the square of a binomial, which is ( (a + b)^2 = a^2 + 2ab + b^2 ). In this case, ( a = 3p ) and ( b = 7 ). Therefore, the product is: [ (3p)^2 + 2(3p)(7) + 7^2 = 9p^2 + 42p + 49. ] So, the final result is ( 9p^2 + 42p + 49 ).
To get 7 using four twos, you can use the following mathematical expression: (2 + 2) x (2 - 2) = 4 x 0 = 0 + 7 = 7. This equation involves addition, subtraction, multiplication, and division, utilizing the four twos to ultimately reach the desired result of 7.
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