To find two numbers where the difference is 7 and the product is 30, we can set up the equations: ( x - y = 7 ) (difference) and ( x \cdot y = 30 ) (product). Solving these equations, we can express ( x ) as ( y + 7 ) and substitute it into the product equation to find the values of ( x ) and ( y ). The numbers that satisfy both conditions are 10 and 3, since ( 10 - 3 = 7 ) and ( 10 \cdot 3 = 30 ).
10 and 3
30*7 = 210
5 x 7 = 35 Therefore, the product is 5 more than 30!
11 and 7
No. 30 x 7-3 = 120 27 x 7 = 189
The difference of 7 and the product of 30 is calculated by subtracting the product of 30 from 7. The product of 30 is 30 multiplied by 7, which equals 210. Therefore, the difference of 7 and the product of 30 is -203.
10 and 3
3 and 10 is one answer. The other answer is -3 and -10.
30*7 = 210
The product of a sum and a difference with 31 times 29 is:(30+1) x (30-1)sum to differencemakea product= 30² - 1²= 900 - 1= 899
5 x 7 = 35 Therefore, the product is 5 more than 30!
Product of 6 and 5 is 30. 30 is 19 less than 49
11 and 7
.82
No. 30 x 7-3 = 120 27 x 7 = 189
23
7 is the product of the sum 16-9