11 and 7
The two whole numbers that have a difference of 4 and a product of 77 are 11 and 7. You can find these numbers by setting up the equations ( x - y = 4 ) and ( x \cdot y = 77 ). Solving these equations, you can express ( x ) as ( y + 4 ) and substitute it into the product equation, leading to ( (y + 4)y = 77 ). This results in the quadratic equation ( y^2 + 4y - 77 = 0 ), which factors to yield the solutions ( y = 7 ) and ( x = 11 ).
It is: (77+32)*(56-45) = 1199
The numbers 40.5 and 36.5 have a difference of 4 and a sum of 77.
77 = 7*11
7 x 11 = 77
11 - 7 = 4 11 x 7 = 77
It is: (77+32)*(56-45) = 1199
The numbers 40.5 and 36.5 have a difference of 4 and a sum of 77.
81 and 4
(8*4) + (8-4) = 32 + 4 = 36 ^ ^ sum ^ product and difference
Sum of 9 and 4 = 13 Difference of 9 and 4 = 5 Product = 13 x 5 = 65.
77 = 7*11
Sum: 16 Product: 48 Difference: 8 Quotient: 3
product means times 6 times 4 = 24 the difference 6 and 4 is 5 22 divided by 5 = 4.4
7 x 11 = 77
436 multiplied by 77 is 33,572.
The two numbers that have a product of 56 and a difference of 10 are 14 and 4. This can be verified as 14 × 4 = 56 and 14 - 4 = 10.