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y8 divided by y3 = y5
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How do you do Y-8 divided by y plus 1 equals 1 over 3 solving for y?
(Y-8)/Y + 1 = 1/3 Multiply both sides by Y Y - 8 + Y = 1/3Y Combine like terms 2Y - 8 = 1/3Y Add 8 to both sides, subtract 1/3 Y from both sides (1 and 2/3)Y = 8 Divide by 1 and 2/3 Y = 4.8
-10 equals 8 plus 3y?
Y=-3. -8 on both sides and divide by3 -10 = 8 + 3y -18 = 3y -6 = y or y = -6
What is the product of 7 and y to the third power when y 2?
To write this algebraically: 7(y^3)|y = 2 Substitute 2 for y: 7(2^3) 2^3 = 8, so substitute 8 for (2^3): 7*8 = 56
What is the answer for these expressions y equals 3 parenthesis -3over2 parenthesis to the power of 2 plus 9 parenthesis -3over2 parenthesis -8?
If you mean: y = 3(-3/2)2+9(-3/2)-8 Then: y = -59/4 or as -14.75
What is 3y plus 5 equals y minus 3?
3y+5=y-3 subtract the y from the other side then: 2y+5=-3 subtract the 5 2y=-8 then divide 2 by both sides and your final answer should be: y= - 4
What is the result if you divide negative 12 x to the 8th power Y to the 8 power by 3 x to the 4th power Y to the 2nd power?
-12 x8 y8 / 3x4 y2 = -4 x4y6 First: divide -12 by 3 which equals -4 Second: divide x to the power of 8 by x to the power of 4 by subtracting the two powers ( 8-4 ) which will equal x to the power of 4 Third: divide y to the power of 8 by y to the power of 2 by subtracting the two powers ( 8-2 ) which will equal y to the power of 6
What is y to the 6th power divided by y to the 5th power?
1.2
How many eighth's are in one third?
To find out how many of x are in y, divide y by x.To find how many 1/8 are in 1/3, divide 1/3 by 1/8:(1/3) / (1/8) = (1/3) x (8/1) = 8/3 = 2 2/3
How do you do Y-8 divided by y plus 1 equals 1 over 3 solving for y?
(Y-8)/Y + 1 = 1/3 Multiply both sides by Y Y - 8 + Y = 1/3Y Combine like terms 2Y - 8 = 1/3Y Add 8 to both sides, subtract 1/3 Y from both sides (1 and 2/3)Y = 8 Divide by 1 and 2/3 Y = 4.8
-10 equals 8 plus 3y?
Y=-3. -8 on both sides and divide by3 -10 = 8 + 3y -18 = 3y -6 = y or y = -6
What is the product of 7 and y to the third power when y 2?
To write this algebraically: 7(y^3)|y = 2 Substitute 2 for y: 7(2^3) 2^3 = 8, so substitute 8 for (2^3): 7*8 = 56
How do you factor Y to the 8th power -81?
89
What is y to the 5th power times y to the 3rd power times y?
y5 * y3 * y = y5 * y3 * y1 = y5+3+1 = y9
25y to the power of 8 divided by 15y to the power of 5?
25y**8/15y**5 25y**3/15 5y**3/3 (5/3)y**3
Solve 2 bracket y plus 3 equals 22?
=> 2(y+3) = 22{divide both sides by 2}=> y+3 = 22/2 = 11{subtract 3 from both sides}=> y = 11-3 = 8y = 8
The only integer n for which n equals x to the y power equals y to the x power for x is not equal to y?
This is definitely false; if x=2 and y=3, x to the y power is 8, but y to the x power is 9, which are not equal.
When dividing exponents what do you do with the exponents give examples?
Not sure about what exactly is being asked, but if I'm interpreting correctly:If you are to divide a^x by a^y (that is, a raised to the x power and a raised to the y power, respectively)(a^x) / (a^y) = a^(x-y)If the numbers are both of the same base, from the exponent in the numerator subtract the exponent in the base.Ex)(3^10) / (3^8) = 3^(10-8) = 3^2 = 9To verify, check that 59049 / 6561 = 9.Remember: negative exponents are positive exponents on the other side of the division sign. To return to the example above, assume we switched the numerator and denominator.Ex) (3^8)/(3^10) = 3^(8-10) = 3^(-2) = 1/(3^2)
