Multiples of 84
a number is divisible by 12 if the number is also divisible by both 3 and 7. You mean a number is divisible by 21 if it is divisible by 3 and 7.
12/21 = 4/7 NOTE : The original fraction can be simplified as both the denominator and numerator are divisible by 3. That is, 3 is a common factor of 12 and 21.
4, 8, 12, 16, and 20.
Because 21 is divisible by numbers other than 1 and 21. 21 is divisible by 1, 3, 7, 21
To find the probability that a randomly selected number from 20 to 30 is divisible by 3 and then divisible by 12, we first identify the numbers in that range: 20, 21, 22, 23, 24, 25, 26, 27, 28, 29, 30. Among these, the numbers divisible by 3 are 21, 24, 27, and 30, which gives us 4 successful outcomes. Next, the only number among these that is also divisible by 12 is 24. Thus, the probability of selecting a number that is divisible by 3 and then, after replacement, is divisible by 12 is the product of the probabilities of each event: ( \frac{4}{11} \times \frac{1}{11} = \frac{4}{121} ).
a number is divisible by 12 if the number is also divisible by both 3 and 7. You mean a number is divisible by 21 if it is divisible by 3 and 7.
The numeral '21' is evenly divisible by 21, 7, 3, and 1.
12/21 = 4/7 NOTE : The original fraction can be simplified as both the denominator and numerator are divisible by 3. That is, 3 is a common factor of 12 and 21.
They're both divisible by 1,3,7, and 21.
There is nothing that is divisible in 37 and 21. Because 37 is a prime number. However, 21 is divisible by 3 and 7.
Because 21 is a multiple of 1, 3, 7 and 21.
4, 8, 12, 16, and 20.
Because 21 is divisible by numbers other than 1 and 21. 21 is divisible by 1, 3, 7, 21
145 is not divisible by 12.
By any multiples of 21
To find the probability that a randomly selected number from 20 to 30 is divisible by 3 and then divisible by 12, we first identify the numbers in that range: 20, 21, 22, 23, 24, 25, 26, 27, 28, 29, 30. Among these, the numbers divisible by 3 are 21, 24, 27, and 30, which gives us 4 successful outcomes. Next, the only number among these that is also divisible by 12 is 24. Thus, the probability of selecting a number that is divisible by 3 and then, after replacement, is divisible by 12 is the product of the probabilities of each event: ( \frac{4}{11} \times \frac{1}{11} = \frac{4}{121} ).
No. 560 is not evenly divisible by 12.