All numbers have cube roots (not necessarily integral cube roots) so every prime has cube roots.
There is no real number multiplied by itself that equals -72, or any negative number, for that matter. In fact there are no even roots of negative numbers. However, odd roots of negative numbers are entirely possible. For instance, the cube root of -64 is -4 ... rather, ( -4 ) ( -4 ) ( -4 ) = -64
The answer depends on "different from WHAT?" Positive cube roots, or negative square roots?
no, -6 is the cube root of -216.
There are 3 cube roots and these are:the real root -1.2599and the complex roots 0.6300 - 1.0911i and its conjugate, 0.6300 + 1.0911i.
All numbers have cube roots (not necessarily integral cube roots) so every prime has cube roots.
there is no cube roots in negative
When (if) you learn more advanced mathematics you will find that there are, in fact 3 cube roots for any non-zero number (in the complex field). In general, there are n nth roots (de Moivre's theorem). However, only one of the cube roots can be a real number, the other two are complex numbers. The reason is that the product of a pair of negative numbers is positive. As a result both x and -x are square roots of x^2. But the product of three negative numbers is itself negative, so for cube roots the signs match up.
Any real number - positive or negative - has exactly one real cube root. Any real number (except zero) has three cubic roots in the complex numbers; but only one of them is real.
One of them is: -5 = -5/1 The other two cube roots are complex numbers.
There is no real number multiplied by itself that equals -72, or any negative number, for that matter. In fact there are no even roots of negative numbers. However, odd roots of negative numbers are entirely possible. For instance, the cube root of -64 is -4 ... rather, ( -4 ) ( -4 ) ( -4 ) = -64
The answer depends on "different from WHAT?" Positive cube roots, or negative square roots?
no, -6 is the cube root of -216.
It depend how many negative numbers are written on the cube.
Negative numbers do not have "real number" square roots.However, they will have two roots (when using imaginary numbers) as do other numbers, where a root including i(square root of -1) is positive or negative.
It lies between the cube roots of 311 and 313.
There are 3 cube roots and these are:the real root -1.2599and the complex roots 0.6300 - 1.0911i and its conjugate, 0.6300 + 1.0911i.