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There are several good websites to find help with radical equations. You tube has several good videos on radical equations that are free of charge.
The answers to equations are their solutions
If a system of equations is inconsistent, there are no solutions.
radical equations have sq roots, cube roots etc. Quadratic equations have x2.
They are called simultaneous equations.
There are several good websites to find help with radical equations. You tube has several good videos on radical equations that are free of charge.
Simultaneous equations have the same solutions.
The answers to equations are their solutions
Equations do have solutions, sometimes they may be a little difficult to figure out.
If a system of equations is inconsistent, there are no solutions.
radical equations have sq roots, cube roots etc. Quadratic equations have x2.
Simultaneous equations have the same solutions
The basic method is the same as for other types of equations: you need to isolate the variable ("x", or whatever variable you need to solve for). In the case of radical equations, it often helps to square both sides of the equation, to get rid of the radical. You may need to rearrange the equation before squaring. It is important to note that when you do this (square both sides), the new equation may have solutions which are NOT part of the original equation. Such solutions are known as "extraneous" solutions. Here is a simple example (without radicals): x = 5 (has one solution, namely, 5) Squaring both sides: x squared = 25 (has two solutions, namely 5, and -5). To protect against this situation, make sure you check each "solution" of the modified equation against the original equation, and reject the solutions that don't satisfy it.
As there is no system of equations shown, there are zero solutions.
I may only be in 8th grade but I am absolutely positive that all quadratic equations have 2 solutions. No - They may have 0,1, or 2 answers For example, the problem x^2 + 8x +16 = 0 has only one solution -4. This is because the radical evaluates to 0 rendering the +/- sign irrelevant.
Simultaneous equations have the same solutions.
1) When solving radical equations, it is often convenient to square both sides of the equation. 2) When doing this, extraneous solutions may be introduced - the new equation may have solutions that are not solutions of the original equation. Here is a simple example (without radicals): The equation x = 5 has exactly one solution (if you replace x with 5, the equation is true, for other values, it isn't). If you square both sides, you get: x2 = 25 which also has the solution x = 5. However, it also has the extraneous solution x = -5, which is not a solution to the original equation.