Yes, the area of an object is most commonly width times length.
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∙ 14y agoIt depends on the shape of the area you are trying to find. The most basic calculation would be the area of a rectangle, which is A = lw (area = length times width).
You have to multiply to find area you have to add to find perimiter
you are suppose to MULTIPLY on area.
Multiply. Be careful what you multiply because different shapes have different rules. Squares are different than triangles, are different than circles, etc. Adding gives you a perimeter.
To find the perimeter you add and to find the area we multiply.
the area
No because you multiply the dimensions
It depends what you are trying to get the area of. For example, to find the area of a square or rectangle you multiply the length times the width. But to find the area of a triangle, you multiply the height times 1/2 of the base. So yes, you usually multiply to find area of a figure, but there may be more steps to the process.
It depends on the shape of the area you are trying to find. The most basic calculation would be the area of a rectangle, which is A = lw (area = length times width).
You have to multiply to find area you have to add to find perimiter
youre trying to find information on whether a product like lanoxin is available
you are suppose to MULTIPLY on area.
To find the length of a triangle or what ever shape your trying to find all you have to do is multiply width times the area. * * * * * Or, if you want the correct answer, you could try to divide the area by the width. That assumes the shape is a rectangle and that the area and width are known!
Multiply. Be careful what you multiply because different shapes have different rules. Squares are different than triangles, are different than circles, etc. Adding gives you a perimeter.
you mean find area? A=LxW
To find the perimeter you add and to find the area we multiply.
You multiply numbers because you're trying to find a multiple. You multiply prime numbers because you're trying to find the smallest common number. You could multiply common composite factors, but the result wouldn't necessarily be least.