No because the range , median, and mode are all diffrent things to find the range subtract the largest and smallest number in the list , to find the median list the numbers in order then cross them out with pairs at the end and beginning of the list, and to find the MODE you just look at the number that appears there MOST times. O.K.
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There is no direct relationship between the range and the median. So knowing that your median is 20 does not automatically give you the range. The median is just the middle value. That does not tell you what the first and last values are, which is what you need to know to find the range. The median of 19, 20 and 21 is 20, and the range is 2. The median of 4, 20 and 79 is also 20, but the range is 75. The median of 8, 16, 17, 23, 50 and 320 is also 20, but the range is 312. So, as you can see, the Median in no way can tell you what the range will be. You need to know what all of the numbers are, or at least the lowest and highest to know the range.
You add all the numbers up and then divide by the amount of numbers there are. e.g 2+4+6= 12, there are 3 numbers (2,4,6) therefore you divide 12 by 3, and you have 4, therefore 12 is the mean. The mode is the most common number, so if you have 3,3,4,5,5,5,5,6 and you need to find the mode, the mode is 5. The median is the middle number, so if you have 1,6,9,114,300 then 9 is the median as it is right in the middle.
To start with we need to find what the current range median mode and mean is for the first 4 results: 80, 88, 94, 98 Current range = 98-80 =18 current median = (88+94)/2 =91 Current mode= there is not one most frequent score so they're all the mode Current mean=(80+88+94+98)/4 =90 When we add the additional score of 85 We have 80,85,88,94,98 Range doesn't change (highest score and lowest score is still the same) Median (middle score) is now 88. This has decreased from before Mode: There is still no one most frequent score as no exam mark occurs twice Mean = (80+85+88+94+98)/5 = 89 This has also decreased. Hope this helps
Well, darling, if you want a range of 7 with a median of 5, you'll need a set of numbers that are evenly spaced. So, let's go with 2, 5, 8, and 11. That way, you've got a range of 7 and a sassy median of 5.
Before I start, you didn't put the range, so I can't completely find the answer. If you can give me the range, I can edit this to make it 100% correct The Median is the "Middle number", so we know that the middle number is 5 ab5cd The mode is the number that is repeated most often, and since it is 3, we know that there has to be two 3s, in order to have more 3s than 5s. (We can't have more or else 5 would be the median) 335cd the mode is the average of all of the numbers (3+3+5+c+d)/5=6 now we just need to do simple math to find C and D 11+c+d=30 C+D=19 The Range is the biggest number minus the smallest number (D-3) If you know the range, you can calculate D, and then find C using C+D=19