No because the range , median, and mode are all diffrent things to find the range subtract the largest and smallest number in the list , to find the median list the numbers in order then cross them out with pairs at the end and beginning of the list, and to find the MODE you just look at the number that appears there MOST times. O.K.
There is no direct relationship between the range and the median. So knowing that your median is 20 does not automatically give you the range. The median is just the middle value. That does not tell you what the first and last values are, which is what you need to know to find the range. The median of 19, 20 and 21 is 20, and the range is 2. The median of 4, 20 and 79 is also 20, but the range is 75. The median of 8, 16, 17, 23, 50 and 320 is also 20, but the range is 312. So, as you can see, the Median in no way can tell you what the range will be. You need to know what all of the numbers are, or at least the lowest and highest to know the range.
You add all the numbers up and then divide by the amount of numbers there are. e.g 2+4+6= 12, there are 3 numbers (2,4,6) therefore you divide 12 by 3, and you have 4, therefore 12 is the mean. The mode is the most common number, so if you have 3,3,4,5,5,5,5,6 and you need to find the mode, the mode is 5. The median is the middle number, so if you have 1,6,9,114,300 then 9 is the median as it is right in the middle.
To start with we need to find what the current range median mode and mean is for the first 4 results: 80, 88, 94, 98 Current range = 98-80 =18 current median = (88+94)/2 =91 Current mode= there is not one most frequent score so they're all the mode Current mean=(80+88+94+98)/4 =90 When we add the additional score of 85 We have 80,85,88,94,98 Range doesn't change (highest score and lowest score is still the same) Median (middle score) is now 88. This has decreased from before Mode: There is still no one most frequent score as no exam mark occurs twice Mean = (80+85+88+94+98)/5 = 89 This has also decreased. Hope this helps
Well, darling, if you want a range of 7 with a median of 5, you'll need a set of numbers that are evenly spaced. So, let's go with 2, 5, 8, and 11. That way, you've got a range of 7 and a sassy median of 5.
Before I start, you didn't put the range, so I can't completely find the answer. If you can give me the range, I can edit this to make it 100% correct The Median is the "Middle number", so we know that the middle number is 5 ab5cd The mode is the number that is repeated most often, and since it is 3, we know that there has to be two 3s, in order to have more 3s than 5s. (We can't have more or else 5 would be the median) 335cd the mode is the average of all of the numbers (3+3+5+c+d)/5=6 now we just need to do simple math to find C and D 11+c+d=30 C+D=19 The Range is the biggest number minus the smallest number (D-3) If you know the range, you can calculate D, and then find C using C+D=19
The median and mode of any number is the same number. The mode of 5 is 5, as is the median of 5. In other words, you need two or more numbers to determine the median and mode of those numbers.
There is no direct relationship between the range and the median. So knowing that your median is 20 does not automatically give you the range. The median is just the middle value. That does not tell you what the first and last values are, which is what you need to know to find the range. The median of 19, 20 and 21 is 20, and the range is 2. The median of 4, 20 and 79 is also 20, but the range is 75. The median of 8, 16, 17, 23, 50 and 320 is also 20, but the range is 312. So, as you can see, the Median in no way can tell you what the range will be. You need to know what all of the numbers are, or at least the lowest and highest to know the range.
You add all the numbers up and then divide by the amount of numbers there are. e.g 2+4+6= 12, there are 3 numbers (2,4,6) therefore you divide 12 by 3, and you have 4, therefore 12 is the mean. The mode is the most common number, so if you have 3,3,4,5,5,5,5,6 and you need to find the mode, the mode is 5. The median is the middle number, so if you have 1,6,9,114,300 then 9 is the median as it is right in the middle.
To start with we need to find what the current range median mode and mean is for the first 4 results: 80, 88, 94, 98 Current range = 98-80 =18 current median = (88+94)/2 =91 Current mode= there is not one most frequent score so they're all the mode Current mean=(80+88+94+98)/4 =90 When we add the additional score of 85 We have 80,85,88,94,98 Range doesn't change (highest score and lowest score is still the same) Median (middle score) is now 88. This has decreased from before Mode: There is still no one most frequent score as no exam mark occurs twice Mean = (80+85+88+94+98)/5 = 89 This has also decreased. Hope this helps
Well, darling, if you want a range of 7 with a median of 5, you'll need a set of numbers that are evenly spaced. So, let's go with 2, 5, 8, and 11. That way, you've got a range of 7 and a sassy median of 5.
Before I start, you didn't put the range, so I can't completely find the answer. If you can give me the range, I can edit this to make it 100% correct The Median is the "Middle number", so we know that the middle number is 5 ab5cd The mode is the number that is repeated most often, and since it is 3, we know that there has to be two 3s, in order to have more 3s than 5s. (We can't have more or else 5 would be the median) 335cd the mode is the average of all of the numbers (3+3+5+c+d)/5=6 now we just need to do simple math to find C and D 11+c+d=30 C+D=19 The Range is the biggest number minus the smallest number (D-3) If you know the range, you can calculate D, and then find C using C+D=19
The median is kind of like the middle number. When you have a set of number you need to sort them from least to greatest, then look for you number that is in the exact middle of them all, that number is your median, if there isn't a number in the exact middle you would add your two middle numbers together, then divide by two and that is your median. The mode is the number that occurs most, so when you sort your data from least to greatest lets say you have one 13, three 14's, and eight 15's your mode would be 15 seeing as that is the number that occurs the most.
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To make the mean true, the student will need to get 94. To make the mode true, the student will need to get 86. To make the median true, the student will need to get 85. As we can see, the three numbers are not the same number. It is impossible the make the three statements true.
Well, isn't that just a happy little problem to solve! To find the missing number when the median is given, you'll want to first list all the numbers in order. Then, if the median is the middle number, you can easily identify the missing number based on whether it falls before or after the median. Just remember, there are no mistakes in math, only happy little accidents!
There is no such data set for 7 numbers. With the maximum at 35 and the range 20, the mode (average) will always be more than 21, even with the lowest numbers possible. e.g. 15 15 15 24 24 24 35 sums to 152, which is 5 higher than the necessary 147 (21 x 7) So you need at least 11 numbers such as 15 15 15 15 15 24 24 24 24 25 35, keeping 24 as the median and the average 21 (231/11).
In general, you cannot. You need to know how many numbers there are and then, in only a select few cases can you find the set.