Take the diameter of the circle times 3.14159 (which is PI).
In order to answer the question, its height is also required.
You would find the area of the inside and outside shape (pretending that the inside shape was not in the outside shape). then, you would take the area of the outside shape and subtract the area of the inside shape.
inside
602 sq inches, on the inside and outside. pi x diameter x height x2
area = pi*radius2Remember, to half the diameter to get the radius.Get the area of the outside circle, and the area of the inside circle, then take the inside area from the outside.I think it would be more helpful to you not to give you the answer. Work it out from this. If you are wondering what pi is, it is 3.14159
Take the diameter of the circle times 3.14159 (which is PI).
In order to answer the question, its height is also required.
The area is four times as large if the diameter doubles.The area of a circle is A = (pi)r2 or (pi)(diameter/2)2Since d is squared, it increases the area by the square of 2 if the diameter is doubled.Try calculating the area for a diameter of 2m, 4m and 8m to prove this.
You would find the area of the inside and outside shape (pretending that the inside shape was not in the outside shape). then, you would take the area of the outside shape and subtract the area of the inside shape.
to divide a pipe into sections measure the outside diameter then multiply by 3.142 this will give you the circumference divide this number by how many sections you require place a mark anywhere on the on the pipe then measure from that mark your answer The best method for calculating the cross section area of a round pipe or tube is to use the following formula: ((D-W)*W)*PI Where as D= Outside Diameter Measurement W= Wall Thickness PI= 3.1416 that is circumference. The answer I have is: diameter squared x .7854 Ex. 3inch pipe (inside diameter) 3 x 3 x .7854= 7.0686
The answer depends on whether the width is inside the 14 metre circle or outside.
In a semicircle, the diameter is the straight line. It is also equal to double the radius, and that property allows it to be used when calculating area and circumference.
inside
no, inside
area is inside the shape/figure
If your ring has an outer radius of 8 mm and an inner one of 5 mm, you will have pi times (routside)2 minus pi times (rinside)2 or about 122.522 square millimeters of area on the top of the ring. Double that if you add in the surface area of the bottom. As to the sides (the inside and outside), we cannot calculate them without a thickness.