no
However 3:4;5 does
Wiki User
∙ 12y agoA triangle with a right angle is a right triangle.
An isosceles right triangle.
Then its not a triangle.
no
No that would be impossible but it can have 2 acute angles and 1 right angle which would be a right angle triangle
1. A triangle is a right triangle if and only if it has a right angle. 2. A triangle has a right angle if and only if it is a right triangle.
1. A triangle is a right triangle if and only if it has a right angle. 2. A triangle has a right angle if and only if it is a right triangle.
That would be a right triangle. Any triangle that has a right angle in it is a right triangle.
Right triangle.
A triangle with 1 right angle and 2 congruent acute angles is both a right triangle and an isosceles triangle.
It is an isosceles right angle triangle
a right triangle has 1 right angle an equilateral triangle has none they are both triangles an equilateral triangle has three equal side a right triangle has only 1 or 2-THANKS! your pretty nice!
1/2*base of triangle*height(the perpendicular)=Area of right angled triangle
You have a proper right triangle with sides of {1 1 √2 } ■
1 on top 6 and 2 on the left side of triangle 5 and 3 on right side of triangle 4 at the bottom of triangle The sum should equal 9 on all sides
No it is impossible a triangle can have: 3 acute angles 1 right and 2 acute angles 1 obtuse and 2 acute angles
Picture a square. now make a line connecting the two diagonal points. If bh is the volume of the rectangle, then we only have half a rectangle for each right triangle giving 1/2 *bh or bh/2. For any other traingle put the base parallel to the ground. Make a perpendicular line to the ground then you have two parts of a triangle divided at a vertex. Each of the these parts has a right angle. Make a second triangle of the same size and if you turn it into the two triangle fromt he first triangle and cut it apart, you can manipulate it to make a rectangle. The two triangles are a rectangle which is bh. divide by two to get one triangle so 1/2*bh or bh/2