x2 + x2 = 2x2 2x^2
x2 - 2x = x(x-2) and that cannot be simplified further.
If you mean: (2x-7y)(x+y) then it is 2x squared -5xy -7y squared
If you mean: y = x squared-2x+1 then it has two equal roots of 1
x^2+x^2=2x^2
x2 + x2 = 2x2 2x^2
x2 - 2x = x(x-2) and that cannot be simplified further.
2 x cosine squared x -1 which also equals cos (2x)
This expression factors as x -1 quantity squared.
No, x + x equals 2x. x times x equals x2. (x times x equals x squared.)
sin2 x = (1/2)(1 - cos 2x) cos2 x = (1/2)(1 + cos 2x) Multiplying both you get (1/4) (1 - cos2 2x) Which is equal to (1/4) (1 - (1/2) (1 + cos 4x) = (1/8) (2 - 1 - cos 4x) = (1/8) (1 - cos 4x) Or If it is the trigonomic function, sin squared x and cosine squared x is equal to one
No. x squared is x times x, whereas 2x is x + x.
If you mean: (2x-7y)(x+y) then it is 2x squared -5xy -7y squared
x2 - 2x = x(x-2)
It is impossible but if it were x squared plus 2x minus 15 the equation would be (x+5) (x-3) with x being equal to either -5 or 3. If the original problem was x squared minus 2x minus 15 the equation would be (x-5)(x+3) and x would be equal to either 5 or -3
Add the x's squared together to get 2x^2+x. You cannot add anymore so the answer is 2x^2+x
It is: -2x squared