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Convert x2 plus y2 equals 2x?
What do you want to convert it to? x2 + y2 = 2x If you want to solve for y: x2 + y2 = 2x ∴ y2 = 2x - x2 ∴ y = (2x - x2)1/2 If you want to solve for x: x2 + y2 = 2x ∴ x2 - 2x = -y2 ∴ x2 - 2x + 1 = 1 - y2 ∴ (x - 1)2 = 1 - y2 ∴ x - 1 = ±(1 - y2)1/2 ∴ x = 1 ± (1 - y2)1/2
How many roots does y equals x2-2x plus 1?
normally an equation with the x value squared there would be two roots. the two roots are positive 1 and postitive 1. since they are they same number there is actually only one root.
How many roots does y equals x2 - 2x plus 1 have It may help to graph the equation?
Factors are (x - 1)(x - 1) so only one root.
X2 plus 2x plus -6 equals 0?
x2 + 2x -6 = 0 x2 + 2x + 1 = 7 (x + 1)2 = 7 x = -1 ± √7
How many roots does y x2 - 6x 9?
1
Convert x2 plus y2 equals 2x?
What do you want to convert it to? x2 + y2 = 2x If you want to solve for y: x2 + y2 = 2x ∴ y2 = 2x - x2 ∴ y = (2x - x2)1/2 If you want to solve for x: x2 + y2 = 2x ∴ x2 - 2x = -y2 ∴ x2 - 2x + 1 = 1 - y2 ∴ (x - 1)2 = 1 - y2 ∴ x - 1 = ±(1 - y2)1/2 ∴ x = 1 ± (1 - y2)1/2
Which equation has equal roots?
Lots, eg x2 - 2x + 1 = 0 which factorises as (x - 1)(x - 1) = 0
How many roots does y equals x2-2x plus 1?
normally an equation with the x value squared there would be two roots. the two roots are positive 1 and postitive 1. since they are they same number there is actually only one root.
How many roots does y equals x2 - 2x plus 1 have It may help to graph the equation?
Factors are (x - 1)(x - 1) so only one root.
What is a polynomial equation of least degree for roots 3 and -5 and 1?
(x - 3)*(x + 5)*(x - 1) = 0 (x2 - 3x + 5x - 15)*(x - 1) = 0 (x2 + 2x - 15)*(x - 1) = 0 (x3 + 2x2 - 15x - x2 - 2x + 15) = 0 ie x3 + x2 - 17x + 15 = 0
X2 - 2x - 5 equals 0?
x2 - 2x - 5 = 0 x2 - 2x + 1 = 6 (x - 1)2 = 6 x - 1 = ± √6 x = 1 ± √6
X2 plus 2x plus -6 equals 0?
x2 + 2x -6 = 0 x2 + 2x + 1 = 7 (x + 1)2 = 7 x = -1 ± √7
What must be added to make x² - 2x plus 5 a perfect square?
negative four: x2 - 2x + 5 = x2 - 2x + 5 - 4 = x2 - 2x + 1 = (x - 1)2
How do you factor x2 2x-3?
x2 + 2x - 3 = (x + 3)(x - 1)
Y equals x2 plus 2x plus 1?
y = x2 + 2x + 1zeros are:0 = x2 + 2x + 10 = (x + 1)(x + 1)0 = (x + 1)2x = -1So that the graph of the function y = x + 2x + 1 touches the x-axis at x = -1.
How many roots does yx2-2x plus 1 have?
If you mean y = x^2 -2x +1 then it has two equal roots of 1 when y = 0
X2 - 2x - 13 equals 0?
x2 - 2x - 13 = 0 x2 - 2x + 1 = 14 (x - 1)2 = 14 x - 1 = ±√14 x = 1 ±√14 x ≈ {4.742, -2.742}
