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Assuming that the two equations are:
2y = x + 4 .................................. 1
y = 12 + 3x ............................. 2
multiplying eqn 2 by two and subtracting it from eqn 1 results in:
0 = 5x + 20, then x = -4
Substituting in eqn 2 with x = -4 results in y = 0
then the common intersection point is (-4, 0)
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What is the slope-intercept form of the equation -3x plus 2y equals 12?
-3x + 2y = 12-3x + 3x + 2y = 3x + 122y = 3x + 122y/2 = 3x/2 + 12/2y = (3/2)x + 6
What is equation of 3x plus 2y equals 8 and 5x plus 2y equals 12?
Both of them are equations!The solution is (x, y) = (2, 1).
What is the solution for 3x plus 2y equals -2 and 6x-y equals 6?
(A) 3x + 2y = -2 (B) 6x - y = 6 (A) + 2(B): 3x + 2y + 12x - 2y = -2 + 12 or 15x = 10 or x = 2/3 substitute this value of x in (A) 2 + 2y = -2 2y = -4 and y = -2 Answer: x = 2/3, y = -2
What is the solution of 2y plus 3x equals 0 x equals -1?
2y + 3x = 0 2y + -3 = 0 2y = 0 + 3 , 2y = 3 y = 3/2 y = 1.5 x = -1
What is the slope-intercept form of the equation-3x plus 2y equals 12?
If: -3x+2y = 12 Then: y = 1.5x+6 in slope-intercept form
