To find the intersection of the equations (2y = 6x) and (y - 3x = -3), we can start by rewriting the first equation as (y = 3x). Substituting (y = 3x) into the second equation gives (3x - 3x = -3), which simplifies to (0 = -3), indicating that there is no solution. Therefore, these two lines are parallel and do not intersect.
If you mean: y = 3x+5 and y = 2x-7 then x = -12 and y = -31
Without any equality signs the given expressions can't be considered to be equations.
Without any equality signs the given terms can't be considered to be equations and so therefore there are no solutions.
To determine the number of solutions for the system of equations given by ( y = 3x - 7 ) and ( y = -3x - 6 ), we can set the two equations equal to each other: [ 3x - 7 = -3x - 6. ] Solving this equation yields ( x = \frac{1}{6} ). Substituting this value back into either equation will give a corresponding ( y )-value, indicating that the system has exactly one solution, which is the point of intersection of the two lines.
Neither y3x-3 nor 3x-y3 are equations, and so neither of them can have a solution. Unfortunately, limitations of the browser used by Answers.com means that we cannot see most symbols. It is therefore impossible to give a proper answer to your question. Please resubmit your question spelling out the symbols as "plus", "minus", "equals" etc. And using ^ to indicate powers (eg x-squared = x^2).
If you mean: y = 2x+2 and y = 3x-1 then it works out as x = 3 and y = 8 meaning that the point of intersection is at (3, 8) on the coordinated plane.
There can be no solution because there is just an expression - no equation nor inequality.
If you mean: y = 3x+5 and y = 2x-7 then x = -12 and y = -31
Tell whether the ordered pair (5, -5) is a solution of the system
Without any equality signs the given expressions can't be considered to be equations.
Without any equality signs the given terms can't be considered to be equations and so therefore there are no solutions.
If you mean: y=3x-4 and the point (2, 1) then the perpendicular equation is 3y=-x+5
5
To determine the number of solutions for the system of equations given by ( y = 3x - 7 ) and ( y = -3x - 6 ), we can set the two equations equal to each other: [ 3x - 7 = -3x - 6. ] Solving this equation yields ( x = \frac{1}{6} ). Substituting this value back into either equation will give a corresponding ( y )-value, indicating that the system has exactly one solution, which is the point of intersection of the two lines.
Neither y3x-3 nor 3x-y3 are equations, and so neither of them can have a solution. Unfortunately, limitations of the browser used by Answers.com means that we cannot see most symbols. It is therefore impossible to give a proper answer to your question. Please resubmit your question spelling out the symbols as "plus", "minus", "equals" etc. And using ^ to indicate powers (eg x-squared = x^2).
Without any equality signs and a missing plus or minus sign the given expressions can't be solved as in an equation.
3x1/5